Answer:
boron has an atomic number of 5
but it has 6 neutron
Explanation:
there is no atom which has 5 neutrons and an atomic number of 5.
Zero, cause the positive and negative work cancel out :)
Answer:
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The area of second coil is ≅ 0.025 
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Explanation:
Given :
No. of turns in the first coil 
No. of turns in the second coil 
Area of first coil 
According to the law of electromagnetic induction,
Induced emf =
Where
magnetic flux.
Since given in question emf of both coil is same so we compare above equation.




Therefore, the area of second coil is ≅ 0.025 
Answer: The correct answer is option (C).
Explanation:
As it is given in the problem, the path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the same mass falls to Jupiter's surface due to its gravitational force.
According to Newton's law of universal gravitational, every particle attracts every other particles in the universe with the gravitational force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The Jupiter is the most massive planet in the solar system. It is also the largest planet in the solar system. The gravity of Jupiter on its surface is 2.4 times that of surface gravity of the Earth.
If a person weighs 100 pounds on the Earth then he would weigh 240 pounds on Jupiter.
Therefore, the correct answer is option (C), the meteor falls to Jupiter faster due to its greater gravitational force.
Answer:
2.9 cm
Explanation:
Assuming that the rear wheel has a radius of 0.330 m
Given that
r(a) = 12 cm -> 0.12 m
w(a) = 0.6 rev/s -> 3.77 rad/s
v = 5 m/s
r(w) = 0.330 m
The speed on any point on the rim at the sprocket in the front is
v(a) = w(a).r(a) = 3.77 * 0.12 = 0.4524 m/s
Also,
v(a) = speed at any point on the chain
v(b) = speed at any point on the rim of the rear sprocket
v(a) = v(b)
where v(b) = w(b).r(b)
Recall that the speed at any point on the rear wheel is v, where
v = w(b).r(w)
5 = w(b) * 0.330
w(b) = 5/0.330
w(b) = 15.15 rad/s
On substituting this in the equation, we have
v(b) = w(b).r(b).
Remember also, that v(a) = v(b), so
0.4524 = 15.15 * r(b)
r(b) = 0.4524 / 15.15
r(b) = 0.029 m -> 2.9 cm
Therefore, the radius of the rear sprocket needed is 2.9 cm