Answer:
C. It is negative
Explanation:
Per Newton's second law, the net force is the mass times the acceleration:
∑F = ma
If the acceleration is negative, the net force is negative.
T = 2*pi*Sqrt (L/g)
T = Period = Time to complete one oscillation, L = Length of the pendulum, g = gravitational acceleration.
Then,
L = {T/(2*pi)}^2*g = {7/(2*pi)}^2*3.711 = 4.606 m
Answer:
Orgasm is one of the most intense pleasures attainable to an organism, yet its underlying mechanisms remain poorly understood. On the basis of existing literatures, this article introduces a novel mechanistic model of sexual stimulation and orgasm. In doing so, it characterizes the neurophenomenology of sexual trance and climax, describes parallels in dynamics between orgasms and seizures, speculates on possible evolutionary origins of sex differences in orgasmic responding, and proposes avenues for future experimentation. Here, a model is introduced wherein sexual stimulation induces entrainment of coupling mechanical and neuronal oscillatory systems, thus creating synchronized functional networks within which multiple positive feedback processes intersect synergistically to contribute to sexual experience. These processes generate states of deepening sensory absorption and trance, potentially culminating in climax if critical thresholds are surpassed. The centrality of rhythmic stimulation (and its modulation by salience) for surpassing these thresholds suggests ways in which differential orgasmic responding between individuals—or with different partners—may serve as a mechanism for ensuring adaptive mate choice. Because the production of rhythmic stimulation combines honest indicators of fitness with cues relating to potential for investment, differential orgasmic response may serve to influence the probability of continued sexual encounters with specific mates.
Explanation:
put it in your own words
Answer:
See below ↓
Explanation:
<u>Step 1 : Diagram</u>
<u>Step 2</u>
- We choose the system to be the spring, the block, and the Earth and it is isolated
- We put all the data in the figure we have created and create a zero level (initial height) of the block to be yₓ = 0 and the final position, when it stops and moves upwards again, to be yₙ = -A
- No external forces are exerted on the system and no energy comes in or out of the system
- Hence,
⇒ ΔE = 0
⇒ Eₙ - Eₓ = 0
⇒ Eₙ = Eₓ
⇒ Kₙ + Uₙ + Pₙ = Kₓ + Uₓ + Pₓ
- Final kinetic energy is 0 at the lowest point
⇒ Uₙ + Pₙ = Uₓ + Pₓ
<u>Step 3</u>
- Initial potential energy is 0 [zero level = initial height]
⇒ Uₙ + Pₙ = Uₓ
- And we know that spring was originally at normal length, so initial spring energy is also 0
⇒ Uₙ + Pₙ = 0
⇒ 1/2kxₙ² + mgyₙ = 0
⇒ 1/2kxₙ² = -mgyₙ
- We know xₙ = A and yₙ = -A from the diagram
⇒ 1/2kA² = -mg(-A)
⇒ 1/2kA² = mgA
⇒ [1/2kA = mg]
<u>Step 4</u>
- Spring force is given by : F = -kx
- Note : x = A
⇒ F = kA
⇒ k = F/A
⇒ Plug 'k' into the equation found at the end of Step 3
⇒ 1/2(F/A)(A) = mg
⇒ 2F = mg
⇒ F = 2mg (a)
<u>Step 5</u>
- We know the spring will stop oscillating and be at rest at the new equilibrium position of the system
⇒ F - mg = 0
⇒ F = mg
⇒ F = -kx
⇒ kyₙ = mg
⇒ yₙ = mg/k
⇒ yₙ = 0.25 x 9.8 / -10
⇒ yₙ = -0.245 m
⇒ yₙ = A
⇒ yₙ = 0.245 m (b)
<u>Step 6</u>
- v(max) = Aω
- v(max) = A√k/m
- v(max) = 0.245 x √(10/0.25)
- v(max) = 1.55 m/s (c)
<span>When a supernova occurs, a very large portion of the stars' mass is lost. In order to create a black hole, at least 30 solar masses is needed, so starting with 10 and losing a large portion of that mass is nowhere near enough to create a black hole. The end result would be a Neutron star.</span>
