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dimulka [17.4K]
3 years ago
5

A small difference between means may not be statistically significant, but it could reach statistical significance with a large

sample becausea) As N increases, the standard error gets smaller, reflecting less variability in sample means, which allows greater sensitivity to detect small but significant differences.b) As N increases, distributions get more heterogeneous, allowing small differences to be detected.c) The overlap between distributions grows as sample size increases.d) The difference between means gets larger as sample size increases
Physics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

Increasing the sample size could make a small difference between means reach statistical significance because;

a) As N increases the standard error gets smaller reflecting less variability in sample means, which allows greater sensitivity to detect small but significant differences

Explanation:

The p-value of a test statistic is used to express the level of significance of the test result. A significant result is typically considered as one with a small p-value of less than or equal to 0.05 at which point we reject the null hypothesis

The p-value can be made smaller by either

1) Increasing the size of the sample (N)

2) Decreasing the standard error

3) Increasing the difference between the hypothesized parameter and the statistic of the sample

The standard error, SE, is given as follows;

SE = \dfrac{\sigma}{\sqrt{N} }

Where;

σ = The standard deviation of the sample

n = The sample size

Therefore the standard error decreases, gets smaller,  with increasing sample size, N

Therefore, the small difference between the sample mean could reach statistical significance with a large sample because as N increases the standard error gets smaller reflecting less variability in sample means, which allows greater sensitivity to detect small but significant differences.

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B  is incorrect
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8 0
3 years ago
A burglar attempts to drag a 108 kg metal safe across a polished wood floor Assume that the coefficient of static friction is 0.
V125BC [204]

Answer:

2.00 m/s²

Explanation:

Given

The Mass of the metal safe, M = 108kg

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Now,

The force against the kinetic friction is given as:

f = \mu_k N = u_k Mg

Where,

N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

f = 0.3\times108\times9.8

or

f = 317.52N

Now, the net force on to the metal safe is

F_{Net}= F-f

Substituting the values in the equation we get

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or

F_{Net}= 216.48

also,

 

F_{Net}= M\timesacceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=\frac{F_{Net}}{M}

or

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or

 

acceleration of the safe=2.00 m/s^2

Hence, the acceleration of the metal safe will be  2.00 m/s²

3 0
3 years ago
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Answer: 2.2x10^4

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Answer:

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