A physics student stands at the top of a hill that has an elevation of 56 meters. he throws a rock and it goes up into the air a
nd then falls back past him and lands on the ground below the path of the rock can be modeled by the equation y=-0.04x^2+1.3x+56 were x is the horizontal distance in meters from the starting point on the top of the hill and y is the height in meters of the rock above the ground a. 56.00 m
b 24.54 m
c. 57.04 m
d. 57.26 m
