I believe it the answer is 3412
<em>Answer:</em>
The equlibrium concentration sof Ca+2 ion willl be 4.9×10∧-3 M
<em>Data Given:</em>
Ksp of CaSO4 = 2.4 × 10∧-5
CaSO4 ⇔ Ca+2 + SO4∧-2
<em>Solution:</em>
Ksp = [Ca+2].[ SO4∧-2]
2.4 × 10∧-5 = [x].[x]= x²
x = 4.9×10∧-3 M
<em>Result:</em>
- The conc. of Ca+2 ion is 4.9×10∧-3 M
Answer:
trans-4-tert-butyl-1-phenylcyclohexanol
Explanation:
The bulky tert-butyl group will occupy the equatorial position in the cyclohexanone ring.
It will hinder approach of the Grignard reagent from the bottom side of the molecule.
The reagent will attack from the top, so the product alcohol will be
<em>trans</em>-4-<em>tert</em>-butyl-1-phenylcyclohexanol.