Complete Question
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.)
mm/s
Answer:
The drift velocity is 
Explanation:
From the question we are told that
The current on the copper is 
The cross-sectional area is
The number of copper atom in the wire is mathematically evaluated

Where
is the density of copper with a value 
is the Avogadro's number with a value 
Z is the molar mass of copper with a value 
So
Given the 1 atom is equivalent to 1 free electron then the number of free electron is

The current through the wire is mathematically represented as

substituting values

=> 
Answer:
what is this a riddle lol it breaks when he either jumps or lands
Explanation:
Answer:
dsin∅ = m×
λ
so, dsin∅red = 3(670nm)
also, dsin∅? =5λ?
however ,if they overlap then dsin∅red = dsin∅?
3(670nm) /5 =402nm
∴λ = 402nm
Explanation:
- (spring constant) (new length of spring - original length of spring) = Force applied to spring.
that is
-kx=F
Did you only have how far the cart traveled? No mass or acceleration or speed or time taken?
the electrons shared between the oxygen and hydrogen atoms spend more time around the oxygen atom nucleus than around the hydrogen atom nucleus