Answer : It’s C.
Cccccccccccccccccccccccccccccccccccccccc
Answer:
pH= 8.45
Explanation:
when working with strong accids pH = -log(Concentration)
so -log(3.58e-9) = 8.446
Answer:
pH = 0.832
Explanation:
pH is given by the formula;
pH = - log [H+]
in this case we are given 0.147 M HCl
HCl is a strong acid and therefore completely dissociates to give out H+ ions,
Therefore; [H+] = [HCl] = 0.147 M
Hence;
pH = - log 0.147 M
<u> = 0.832 </u>
We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
Formula
V/T = V1/T1
Givens
V = 430 L
T = - 42 °C = - 42 + 273 = 231°K
V1 = ??
T1 = 18°C + 273 = 291°K
The pressure is a constant.
Solution
420/231 = V1/291 Multiply by 291
420*291 / 231 = V1
V1 = 122220 / 231
V1 = 521.1 L
