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irakobra [83]
3 years ago
14

Which description correctly characterizes the acidity or basicity of a solution? The higher the pH is, the more the hydroxide io

n concentration decreases and the more acidic the solution becomes. The higher the pH is, the more the hydroxide ion concentration increases and the more basic the solution becomes. The lower the pH is, the more the hydronium ion concentration decreases and the more acidic the solution becomes. The lower the pH is, the more the hydronium ion concentration increases and the more basic the solution becomes.

Chemistry
2 answers:
Free_Kalibri [48]3 years ago
8 0

Answer:

The other person explained it well but attached is a picture

Explanation:

joja [24]3 years ago
7 0

Answer:

The higher the pH is, the more the hydroxide ion concentration increases and the more basic the solution becomes.

Explanation:

  • When the pH of a solution is less than 7, then solution is called acidic and as the pH decreases the concentration of Hydronium ion increases.
  • When the pH is about 7, then the  solution is said to be neutral. On the other hand, when  the pH is greater than 7, the solution is is said to be basic and as the pH increases the concentration of Hydroxide ions increases.
  • Therefore, An acidic solution has a higher concentration of hydrogen ions compared to the concentration of hydroxide ions.
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Equal volumes of two solutions, one containing a strong acid at pH 2 and the other containing a strong base at pH 12, are mixed.
mash [69]

Answer:

7  

Explanation:

Assume we have 1 L of each solution.

Solution 1

\text{[H$^{+}$]}= 10^\text{-pH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of H}^{+} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol H}^{+}}{\text{1 L solution}} = 10^{-2}\text{ mol H}^{+}

Solution 2

pH = 12

pOH = 14.00 - pOH = 14.00 - 12 = 2.0

\text{[OH$^{-}$]}= 10^\text{-pOH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of OH}^{-} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol OH}^{-}}{\text{1 L solution}} = 10^{-2}\text{ mol OH}^{-}

3. pH after mixing

               H⁺  +  OH⁻ ⟶ H₂O

I/mol:     10⁻²    10⁻²  

C/mol:   -10⁻²   -10⁻²

E/mol:      0        0

The H⁺ and OH⁻ have neutralized each other. The pH will be that of pure water.

pH = 7

8 0
4 years ago
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