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Reil [10]
3 years ago
5

A net force of 125 N accelerates a 25.0 kg mass. What is the resulting acceleration?

Physics
2 answers:
Neko [114]3 years ago
5 0

Answer: a=5 m/s^2

Explanation:

The acceleration of an object can be calculated by using Newton's second law:

F=ma

where

F is the net force applied on the object

m is the mass of the object

a is its acceleration

In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:

a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2

tester [92]3 years ago
4 0
We Know, F = m*a
Here, m = 0.25 Kg
F = 125 N

Substitute it into the expression, 
125 = 25 * a
a = 125/25
a = 5

So, your final answer is 5

Hope this helps!
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8 0
3 years ago
A rock with density 1900 kg/m3 is suspended from the lower end of a light string. When the rock is in air, the tension in the st
wel

Answer:

the tension T2 when the rock is completely immersed is T2 =  29.05 N

Explanation:

from Newton's second law

F= m*a

where F= force , m= mass , a= acceleration

when the rock is suspended ,a=0 since it is at rest. Then

T1 - m*g = 0 , T1= tension when suspended in air , g= gravity

assuming constant density of the rock

m= ρ rock *V , where  ρ rock = density of the rock , V= volume

thus

T1= m*g = ρ rock *g*V

V=  T1/(ρ rock *g)

when the rock is submerged in oil , it receives an upward force that equals the weight of the volume of displaced oil (V displaced). Since it is completely submerged the volume displaced is the volume of the rock V=Vdisplaced  

When the rock is at rest , then

F= m*a=0

T2 + ρ oil *g*V displaced - ρ rock *g*V  =0

T2 = ρ rock *g*V - ρ oil *g*V = g*V (ρ rock - ρ oil)

T2 = g*V (ρ rock - ρ oil) = T1/(ρ rock *g) *g * (ρ rock - ρ oil)

T2 = T1 * (ρ rock - ρ oil)/ρ rock

replacing values

T2 = 48 N * (1900 kg/m3- 750 kg/m3)/ 1900 kg/m3 = 29.05 N

T2 =  29.05 N

3 0
3 years ago
What happens when sediment builds up over time
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3 years ago
Read 2 more answers
susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o
prisoha [69]

Answer:

3600joules

Explanation:

formula :W=FS

W=work done (J)

F=force (N)

S=displacement moved in the direction of force (m)

200N×18m

=3600J

3 0
2 years ago
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