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umka2103 [35]
3 years ago
6

Convert 180 km/h to m/s using dimensional analysis.

Physics
1 answer:
Stels [109]3 years ago
6 0

Answer:

50m/s2

Explanation:

1kmph =5/18 mls2

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You and your dog go for a walk to the park. On the way, your dog takes many side trips to chase squirrels or examine fire hydran
Marysya12 [62]

Answer:

yes. We will have the same displacement.

Explanation:

It's in the definition of a displacement that " displacement is the change in position and if the initial and final position is same then the displacement will be zero". So in the park from starting position if we end up walking at the same position then our displacement will be zero because our initial and final positions are same.

3 0
4 years ago
Select the correct statement about osmolarity. a) Osmolarity measures the moles of solute per liter of solution. b) The contents
8090 [49]

Answer:

a) Osmolarity measures the moles of solute per liter of solution.

Explanation:

Osmolarity is defined as the number of moles of solute that contribute to the osmotic pressure, per liter of solution, of solution. That is, the measurement of the solute concentration. The prefix "osmo-" indicates the possible variation of the osmotic pressure in the cells, which will occur when the solution is introduced into the body.

7 0
4 years ago
The scientist most often credited with the idea that matter can have wave-like properties is:
Flura [38]
I believe the correct answer from the choices listed above is option B. The scientist most often credited with the idea that matter can have wave-like properties is de Broglie. He <span>related E=mc^2, E=hf and p=mv in order to acquire the de Broglie wavelength, whose formula λ=h/p where h is Planck's constant and p is momentum of the particle.</span>
6 0
4 years ago
Read 2 more answers
A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c
seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2

So the volume flow rate along the pipe is

\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s

We can use the similar logic to find the cross-section area at the refinery

A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2

The radius of the pipe at the refinery is:

A_r = \pi r^2

r^2 =A_r/\pi = 0.446/\pi = 0.141

r = \sqrt{0.141} = 0.377m

So the diameter is twice the radius = 0.38*2 = 0.754m

6 0
3 years ago
Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68
lions [1.4K]

Answer:

The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

Given:

Initial vertical height is, y_0=1500\ m

Initial horizontal velocity is, u_x=688\ m/s

Initial vertical velocity is, u_y=0(\textrm{Horizontal velocity only initially)}

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is S=y-y_0=0-1500=-1500\ m

Acceleration in the vertical direction is due to gravity, g=-9.8\ m/s^2

Therefore, the displacement of the bomb is given as:

S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s

So, the bomb will remain in air for 17.5 s before hitting the ground.

5 0
3 years ago
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