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musickatia [10]
2 years ago
15

An electron is moving at a speed of 2.50 ✕ 104 m/s in a circular path of radius of 3.0 cm inside a solenoid. The magnetic field

of the solenoid is perpendicular to the plane of the electron's path. The solenoid has 25 turns per centimeter. (a) Find the strength of the magnetic field inside the solenoid. µT (b) Find the current in the solenoid. mA
Physics
1 answer:
bogdanovich [222]2 years ago
5 0

Answer:

Explanation:  you would need to divide the two numbers

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A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w
steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

h = L - L\cos{31°} = L(1 - \cos{31°})

so its initial gravitational potential energy U_0 is

U = mgh = mgL(1 - \cos{31°})

\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})

\:\:\:\:\:=0.23\:\text{J}

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U

We know that the initial kinetic energy K_0, as well as its final gravitational potential energy U are zero so we can write the conservation law as

mgL(1 - \cos{31°}) = \frac{1}{2}mv^2

Note that the mass gets cancelled out and then we solve for the velocity v as

v = \sqrt{2gL(1 - \cos{31°})}

\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}

\:\:\:\:\:= 1.3\:\text{m/s}

5 0
2 years ago
Read 2 more answers
How many joules are required to heat .250 kg of liquid water from 0 °C to 100 °C ?
dedylja [7]

Answer:

Specific heat of water is 4.186 J/g/C. The heat required to raise the temperature by

is

Here  is mass of water being heated,  specific heat of water and  change in temperature.

Here .

Heat energy required is

Explanation:

4 0
2 years ago
3. The velocity of sound is 332 m/s. Answer the following questions:
Angelina_Jolie [31]

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}

The longest wavelength that can be heard by the human ear is 16.6 m

\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}

The shortest wavelength that can be heard by the human ear is 0.0166 m.

3 0
2 years ago
How to delete question​
Marrrta [24]
Oh your from the other question you made I just saw it LOL.
But heres the answer click the 3 dots on the question you made or you can ask a Moderator or Administrator to remove your question with a reason.
6 0
2 years ago
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For horizontally-launched projectiles, which of the following describes acceleration in both directions with a = 0 and a = -9.8m
natulia [17]

Answer:

4 is the best option for it as there are some stuff in grade to ye

5 0
3 years ago
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