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musickatia [10]
3 years ago
15

An electron is moving at a speed of 2.50 ✕ 104 m/s in a circular path of radius of 3.0 cm inside a solenoid. The magnetic field

of the solenoid is perpendicular to the plane of the electron's path. The solenoid has 25 turns per centimeter. (a) Find the strength of the magnetic field inside the solenoid. µT (b) Find the current in the solenoid. mA
Physics
1 answer:
bogdanovich [222]3 years ago
5 0

Answer:

Explanation:  you would need to divide the two numbers

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5. Based on the data collected by the students, what is the tangential velocity of
malfutka [58]

The tangential velocity of the ball is 0.63 m/s.

<h3>What is tangential speed?</h3>

Tangential speed is the linear component of the speed of any object moving along a circular path.

v = ωr

where;

  • v is the tangential speed
  • ω is the angular speed (rad/s)
  • r is the radius of the circle

At a given radius of the circle = 0.3 m

Let the number of revolution per min = 20 rev/min

\omega = 20 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} = 2.1 \ rad/s

v = ωr

v = 2.1 x 0.3

v = 0.63 m/s

Thus, the tangential velocity of the ball is 0.63 m/s.

Learn more about tangential velocity here: brainly.com/question/25780931

8 0
2 years ago
A 9.8-g bullet is fired into a stationary block of wood having mass m = 5.04 kg. The bullet imbeds into the block. The speed of
pogonyaev

Answer:

313.8 m/s

Explanation:

Momentum p must be conserved.

The momentum before the collision:

p=m_{bullet}v_{bullet} + m_{block}v_{block}

The momentum after the collision:

p=(m_{bullet}+m_{block})v_{bullet+block}

Solving both equations:

v_{bullet}=\frac{(m_{bullet}+m_{block})v_{bullet+block}}{m_{bullet}}

6 0
4 years ago
An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the
monitta

Answer:

The acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

Explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval.  Let a is the acceleration. Using the definition of acceleration as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{22.2-16.67}{5}\\\\a=1.106\ m/s^2

Let d is the distance covered. Using the third equation of motion to find it as follows :

v^2-u^2=2as\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(22.2)^2-(16.67)^2}{2\times 1.106}\\\\s=97.17\ m

So, the acceleration is 1.106\ m/s^2 and the distance covered is 97.17 m.

7 0
3 years ago
What do the length of the cord and gravity determine for a pendulum?
rusak2 [61]

Answer:  C

Period/ Period of the pendulum.

Content:  

Simple pendulum is a small diameter bob which is suspended from light cord or string. The string is strong enough to stretch.

Pendulums are quiet common in use such as clocks, swings etc.,

From the simple pendulum we can find conditions under which it performs simple harmonic motion and we can also derive the expressions for Period of pendulum, frequency etc.

<em>Period of a pendulum/Time period is given by the following expression</em>

<em>               </em><em> T =2π.√(L/g) seconds </em>

<em>                 </em><em>T = period of pendulum in seconds</em>

<em>                 L = Length of the string/cord in meters</em>

<em>                 g = gravitational force in m/s²   ( g = 9.8 m/s² )</em>

<em>Period of pendulum is independent on mass of the bob.</em>

<em>So, The relation between length of the cord and gravity is used to determine the period of pendulum</em>


4 0
3 years ago
Rewrite the following sentence in the negative form &gt;Each library contains 3000 brand new books
otez555 [7]
None of the libraries have up to 3000 brand new books
3 0
2 years ago
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