Answer:
Option B
Explanation:
Magnification of Microscope is
Mo= Magnification of objective lens and
Me= magnification of the eyepiece.
Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.
Magnification,
when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.
Thus. Magnification will increase by decreasing the focal length.
The correct answer is Option B i.e. using shorter focal length
Because the net force must be zero, we conclude that the magnitude of the force is 1500 newtons, and the direction is in the positive axis.
<h3>
What is the magnitude and direction of the third force?</h3>
By Newton's laws, we know that if the net force applied to an object is different than zero, then the object is accelerated.
In this case, we know that the object moves with constant velocity, so there is no acceleration, meaning that the net force is equal to zero.
Then we must have:
F1 + F2 + F3 = 0N
Replacing F1 and F2 we get:
-3000 N + 1500N + F3 = 0
F3 = 3000N - 1500 N = 1500N
Then the magnitude of the force is 1500 newtons, and the direction is in the positive axis.
If you want to learn more about Newton's laws, you can read:
brainly.com/question/10454047
Answer:
You are finding acceleration, so it would be 15 m/s2
Explanation:
30 divided by 2
Answer:
The amount of energy wasted by light bulb 2 = 70 J
Explanation:
Sankey diagrams are used to graphically indicate the proportional flow rate of a quantity
The labelled Sankey diagrams, here, indicate the energy transfers in two light bulbs, light bulb 1 and light bulb 2
From the labelled Sankey diagrams, we have;
For light bulb 1, the input energy = 80 J
The useful energy = 40 J
The wasted energy = 80 - 40 = 40 J
For light bulb 2, the input energy = 80 J
The useful energy = 10 J
Therefore, the wasted energy = 80 - 10 = 70 J
The amount of energy wasted by light bulb 2 = 70 J.
Answer:
F2 and F3 forms action-reaction pair
Explanation:
In accordance to Newton's third law of motion, action-reaction pairs are formed.
The law is based on the fact that for every action there exist a force that acts opposite and equal to the action force resulting in action reaction pair as they act on different object leading to the motion.
Here, the hot air balloon is in vertically upward motion at constant speed, the speed remains same resulting in no acceleration and also the weight of the student exerts a force opposed by the force exerted by the balloon
