An engineer can increase the magnitude of the magnification of a compound microscope by
1 answer:
Answer:
Option B
Explanation:
Magnification of Microscope is
Mo= Magnification of objective lens and
Me= magnification of the eyepiece.
Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.
Magnification,
when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.
Thus. Magnification will increase by decreasing the focal length.
The correct answer is Option B i.e. using shorter focal length
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Explanation:
Expression to calculate thermal resistance for iron () is as follows.
where, = length of the iron bar
= thermal conductivity of iron
= Area of cross-section for the iron bar
Thermal resistance for copper () = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]
where, = length of copper bar
= thermal conductivity of copper
= Area of cross-section for the copper bar
Now, expression for the transfer of heat per unit cell is as follows.
Q =
Putting the given values into the above formula as follows.
Q =
=
= 2.92 Joule
It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,
P =
Here, T is 1 second so, power conducted is equal to heat transferred.
So, P = 2.92 watt
Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.