The magnetic force on a wire 274 cm long is . If electrons move through the wire in 1.90 s, what is the magnitude of magnetic fi
1 answer:
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Let A = i+j+k be a vector and B = 3 be any scalar,
Multiplying A and B,
AB = (i+j+k)3 = 3i+3j+3k
Which is a new vector whose direction is same as the old but it's 3 times greater in length than the old vector(i+j+k).
Now, dividing A and B,
A/B = (i+j+k)/3 =
Which is again a new vector whose direction is same as the old but now it's 1/3 times small in length than the old vector.
Direction is same because we multiplied by positive scalar. If we multiply A by suppose -1, -4, -1000000 or any negative number, it's direction will reverse.
Thus, if we multiply a vector with scalar, it's length increases. If we divide, it shrinks.
Multiplying A and B,
AB = (i+j+k)3 = 3i+3j+3k
Which is a new vector whose direction is same as the old but it's 3 times greater in length than the old vector(i+j+k).
Now, dividing A and B,
A/B = (i+j+k)/3 =
Which is again a new vector whose direction is same as the old but now it's 1/3 times small in length than the old vector.
Direction is same because we multiplied by positive scalar. If we multiply A by suppose -1, -4, -1000000 or any negative number, it's direction will reverse.
Thus, if we multiply a vector with scalar, it's length increases. If we divide, it shrinks.
Answer:
The voltage drop through which the proton moves is 39.1 V.
Explanation:
Given that,
Distance = 4.76 cm
Time
We need to calculate the acceleration
Using equation of motion
Where, s = distance
a = acceleration
t = time
Put the value in the equation
We need to calculate the voltage drop
Using formula of electric field
....(I)
Using newton's second law
....(II)
Put the value of F in equation (I) from equation (II)
Where, q = charge
a = acceleration
d = distance
m= mass of proton
Put the value into the formula
Hence, The voltage drop through which the proton moves is 39.1 V.