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Alja [10]
4 years ago
9

The magnetic force on a wire 274 cm long is . If electrons move through the wire in 1.90 s, what is the magnitude of magnetic fi

eld that is perpendicular to the wire?
Physics
1 answer:
kozerog [31]4 years ago
3 0

Answer:

Matter & Energy

Math Review

Kinematics  

Defining Motion

Graphing Motion

Kinematic Equations

Free Fall

Projectile Motion

Relative Velocity

Dynamics

Newton's 1st Law

Free Body Diagrams

Newton's 2nd Law

Static Equilibrium

Newton's 3rd Law

Friction

Ramps and Inclines

Atwood Machines

Momentum

Impulse & Momentum

Conservation Laws

Types of Collisions

Center of Mass

UCM & Gravity

Uniform Circular Motion

Gravity

Kepler's Laws

Rotational Motion  

Rotational Kinematics

Torque

Angular Momentum

Rotational KE

Work, Energy & Power

Work

Hooke's Law

Power

Energy

Conservation of Energy

Fluid Mechanics  

Density

Pressure

Buoyancy

Pascal's Principle

Fluid Continuity

Bernoulli's Principle

Thermal Physics  

Temperature

Thermal Expansion

Heat

Phase Changes

Ideal Gas Law

Thermodynamics

Electrostatics  

Electric Charges

Coulomb's Law

Electric Fields

Potential Difference

Capacitors

Current Electricity  

Electric Current

Resistance

Ohm's Law

Circuits

Electric Meters

Circuit Analysis

Magnetism  

Magnetic Fields

The Compass

Electromagnetism

Microelectronics  

Silicon

P-N Junctions

Transistors

Digital Logic

Processing

Integration

Waves & Sound  

Wave Characteristics

Wave Equation

Sound

Interference

Doppler Effect

Optics  

Reflection

Refraction

Diffraction

EM Spectrum

Modern Physics  

Wave-Particle Duality

Models of the Atom

M-E Equivalence

The Standard Model

Relativity

MAGNETISM

Magnetic Fields

The Compass

Electromagnetism  

Electromagnetism

In 1820, Danish physicist Hans Christian Oersted found that a current running through a wire created a magnetic field, kicking off the modern study of electromagnetism.

Moving electric charges create magnetic fields. You can test this by placing a compass near a current-carrying wire. The compass will line up with the induced magnetic field.

To determine the direction of the electrically-induced magnetic field due to a long straight current-carrying wire, use the first right hand rule (RHR) by pointing your right-hand thumb in the direction of positive current flow. The curve of your fingers then shows the direction of the magnetic field around a wire (depicted at right).

You can obtain an even stronger magnetic field by wrapping a coil of wire in a series of loops known as a solenoid and flowing current through the wire. This is known as an electromagnet. You can make the magnetic field from the electromagnet even stronger by placing a piece of iron inside the coils of wire. The second right hand rule tells you the direction of the magnetic field due to an electromagnet. Wrap your fingers around the solenoid in the direction of positive current flow. Your thumb will point toward the north end of the induced magnetic field, as shown below.

Explanation:

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Readme [11.4K]

Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

H = 4.905 m

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

a = g = 9.81 m/s^2

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

v_f = 0

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

\Delta y = 0 = v_y t + \frac{1}{2} at^2

0 = v_y (2) - \frac{1}{2}(9.81)(2^2)

v_y = 9.81 m/s

Part d)

at the maximum height position we know that the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a d

here we have

0 - (9.81^2) = 2(-9.81)H

H = 4.905 m

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maks197457 [2]
  • Displacement = 10 m
  • Time = 5 s
  • We know,
  • velocity \:  \:  =  \frac{displacement}{time}  \\
  • Therefore, the car's velocity
  • =  \frac{10}{5} m/s \\  = 2m/s
<h3>Answer:</h3>

The car's velocity is 2 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Answer:

I believe the answer to be B.

Explanation:

Without food, the whales would die.

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