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Alja [10]
3 years ago
9

The magnetic force on a wire 274 cm long is . If electrons move through the wire in 1.90 s, what is the magnitude of magnetic fi

eld that is perpendicular to the wire?
Physics
1 answer:
kozerog [31]3 years ago
3 0

Answer:

Matter & Energy

Math Review

Kinematics  

Defining Motion

Graphing Motion

Kinematic Equations

Free Fall

Projectile Motion

Relative Velocity

Dynamics

Newton's 1st Law

Free Body Diagrams

Newton's 2nd Law

Static Equilibrium

Newton's 3rd Law

Friction

Ramps and Inclines

Atwood Machines

Momentum

Impulse & Momentum

Conservation Laws

Types of Collisions

Center of Mass

UCM & Gravity

Uniform Circular Motion

Gravity

Kepler's Laws

Rotational Motion  

Rotational Kinematics

Torque

Angular Momentum

Rotational KE

Work, Energy & Power

Work

Hooke's Law

Power

Energy

Conservation of Energy

Fluid Mechanics  

Density

Pressure

Buoyancy

Pascal's Principle

Fluid Continuity

Bernoulli's Principle

Thermal Physics  

Temperature

Thermal Expansion

Heat

Phase Changes

Ideal Gas Law

Thermodynamics

Electrostatics  

Electric Charges

Coulomb's Law

Electric Fields

Potential Difference

Capacitors

Current Electricity  

Electric Current

Resistance

Ohm's Law

Circuits

Electric Meters

Circuit Analysis

Magnetism  

Magnetic Fields

The Compass

Electromagnetism

Microelectronics  

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Processing

Integration

Waves & Sound  

Wave Characteristics

Wave Equation

Sound

Interference

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Refraction

Diffraction

EM Spectrum

Modern Physics  

Wave-Particle Duality

Models of the Atom

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The Standard Model

Relativity

MAGNETISM

Magnetic Fields

The Compass

Electromagnetism  

Electromagnetism

In 1820, Danish physicist Hans Christian Oersted found that a current running through a wire created a magnetic field, kicking off the modern study of electromagnetism.

Moving electric charges create magnetic fields. You can test this by placing a compass near a current-carrying wire. The compass will line up with the induced magnetic field.

To determine the direction of the electrically-induced magnetic field due to a long straight current-carrying wire, use the first right hand rule (RHR) by pointing your right-hand thumb in the direction of positive current flow. The curve of your fingers then shows the direction of the magnetic field around a wire (depicted at right).

You can obtain an even stronger magnetic field by wrapping a coil of wire in a series of loops known as a solenoid and flowing current through the wire. This is known as an electromagnet. You can make the magnetic field from the electromagnet even stronger by placing a piece of iron inside the coils of wire. The second right hand rule tells you the direction of the magnetic field due to an electromagnet. Wrap your fingers around the solenoid in the direction of positive current flow. Your thumb will point toward the north end of the induced magnetic field, as shown below.

Explanation:

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A power company charges its customers for electricity based upon which one of the following?a. powerb. energyc. power per unit o
Vlad [161]

B. Energy

A power company charges its customers for electricity based upon B. Energy.

<h3>Explanation:</h3>

Kilo-watt Hours (kWh) is the unit that measures the electricity consumption of customers. Since Power is defined as the rate at which electrical energy is transferred by an electrical circuit per unit time,

P = \frac{E}{t} \\E= P\times t

If energy is transmitted at a constant rate over a period of time, the total energy in kilowatt hours is the product of power in kilowatts(kW) and time in hours (h)

1\ kWh = 3.6\times 10^6\ Joules

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3 years ago
Two point charges are arranged in a line with point P, which is on the right. The
MAVERICK [17]

Answer:

chicken

Explanation:

you like chicken and want to eat it

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When sedimentary rock is exposed to heat and pressure, what does it change into?
patriot [66]
Metamorphic rock this possess often occurs in the mantle
7 0
3 years ago
A 1.50-m string of weight 0.0125 N is tied to the ceil- ing at its upper end, and the lower end supports a weight W. Ignore the
Elena L [17]

The wave equation is missing and it is y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Answer:

A) 0.0534 seconds

B) 0.67N

C) 41

D) (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

Explanation:

we are given weight of string = 0.0125N

Thus, since weight = mg

Then, mass of string = 0.0125/9.8

Mass of string = 1.275 x 10⁻³ kg

Length of string; L= 1.5 m .

mass per unit length; μ = (1.275 x 10⁻³)/1.5

μ = 0.85 x 10⁻³ kg/m

We are given the wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Now if we compare it to the general equation of motion of standing wave on a string which is:

y(x,t) = Acos(Kx − ω t)

We can deduce that

angular velocity;ω = 4830 rad/s

Wave number;k = 172 rad/m

A) Velocity is given by the formula;

V = ω/k

Thus, V = 4830/172 m/s

V = 28.08 m /s

Thus time taken to go up the string = 1.5/28.08 = 0.0534 seconds

B) We know that in strings,

V² = F/μ

Where μ is mass per unit length and V is velocity.

Thus, F = V²*μ =28.08² x 0.85 x 10⁻³

F = 0.67N

C) Formula for wave length is given as; wave length;λ = 2π /k

λ = 2 x π/ 172

λ = 0.0365 m

Thus, number of wave lengths over whole length of string

= 1.5/0.0365 = 41

D) The equation for waves traveling down the string

= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

8 0
3 years ago
Determine the number of ways to throw two die and get the number 11, as well as the probability of getting 11.
Ivenika [448]

Answer:

1/18

Explanation:

The number of ways in which two die can be thrown is the sample space of the experiment

(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)

(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)

(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)

(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)

(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)

(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)

From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)

\text{Probability of getting 11}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\\\Rightarrow \text{Probability of getting 11}=\frac{2}{36}\\\Rightarrow \text{Probability of getting 11}=\frac{1}{18}=0.056

∴ Probability of getting 11 is<u> 1/18</u>

8 0
3 years ago
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