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Fittoniya [83]
3 years ago
10

Following are several z-transforms. For each one, determine inverse z-transform using both the method based on the partial-fract

ion expansion and the Taylor's series method based on the use of long division. X(z) = 1 - z^-1/1 - 1/4Z^-2, |z| > 1/2.

Engineering
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

For now the answer to this question is only for partial fraction. Find attached.

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Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity. The thermal energy concentrated in a CSP plant can be stored and used to produce electricity when it is needed, day or night. Today, roughly 1,815 megawatts (MWac) of CSP plants are in operation in the United States.

Parabolic Trough
Parabolic trough systems use curved mirrors to focus the sun’s energy onto a receiver tube that runs down the center of a trough. In the receiver tube, a high-temperature heat transfer fluid (such as a synthetic oil) absorbs the sun’s energy, reaching temperatures of 750°F or higher, and passes through a heat exchanger to heat water and produce steam. The steam drives a conventional steam turbine power system to generate electricity. A typical solar collector field contains hundreds of parallel rows of troughs connected as a series of loops, which are placed on a north-south axis so the troughs can track the sun from east to west. Individual collector modules are typically 15-20 feet tall and 300-450 feet long.

Compact Linear Fresnel Reflector
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3 0
3 years ago
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Pls pls pls pls plsss someone help pls
snow_tiger [21]

Answer:

I would like to help can you take a picture without the bot telling you something. Maybe then I can figure it out.

6 0
2 years ago
An AC circuit has a resistor, capacitor and inductor in series with a 120 V, 60 Hz voltage source. The resistance of the resisto
aliina [53]

Answer:

(i) 3.5385 ohm, 3.768 ohm (ii) 39.89 A (III) 4773.857 W (vi) 348 var (vii) 0.9973 (viii) 4.1796°

Explanation:

We have given voltage V =120 volt

Frequency f=60 Hz

Resistance R =3 ohm

Inductance L =0.01 H

Capacitance C =0.00075 farad

(i) reactance of of inductor X_L=\omega L=2\pi fL=2\times 3.14\times 60\times 0.01=3.768ohm

X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 60\times 0.00075}=3.5385ohm

(ii) Total impedance Z=\sqrt{R^2+(X_L-X_C)^2}=\sqrt{3^2+(3.768-3.5385)^2}=3.008ohm

Current i=\frac{V}{Z}=\frac{120}{3.008}=39.89A

(viii) power factor cos\Phi =\frac{R}{Z}=\frac{3}{3.008}=0.9973

(VII) cos\Phi =0.9973

\Phi =4.1796^{\circ}

So power factor angle is 4.1796°

(iii) Apparent power P=VICOS\Phi =120\times 39.89\times 0.9973=4773.875W

(vi) Reactive power Q=VISIN\Phi =120\times 39.89\times SIN4.17^{\circ}=348var

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3 years ago
Give me a smart goals to achieve ​
S_A_V [24]
Just a suggestion: i would start with short-term goals to help you build up to your long-term goals
7 0
3 years ago
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While supporting load P, the maximum contraction permitted in a 4.75-m long pipe column is 7 mm. Given that E =180 GPa for the c
Alexeev081 [22]

Answer:

\mathbf{stress \ \sigma = 264.6 \ Mpa}

Explanation:

From the concept of Hooke's  Law,

E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

where;

strain \ \varepsilon = \dfrac{change \ in \ dimension }{original \ dimension}

strain \ \varepsilon = \dfrac{7 \ mm }{4.75 \times 10^{3} \ mm}

strain \ \varepsilon =0.00147368

Recall:

E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

stress \ \sigma = E \times { strain \  \varepsilon}

stress \ \sigma = 180 \times 10^{3} \ Mpa \times 0.00147

\mathbf{stress \ \sigma = 264.6 \ Mpa}

Thus, the stress in the pipe at the maximum allowable contraction = 264.6 Mpa

7 0
3 years ago
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