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enyata [817]
3 years ago
6

Magnet A doesn't have its poles labeled, but Magnet B has a clearly labeled north and south pole. If the

Physics
2 answers:
kondor19780726 [428]3 years ago
5 0

D:   The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D:  The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

Read more on Brainly.com - brainly.com/question/14114321#readmore

dusya [7]3 years ago
4 0

Answer:

D:   The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D:  The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

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The temperature inside a vehicle can rise ____ degrees higher than the outside temperature.
Elis [28]

Answer:

Generally, 40 to 50 degrees

Explanation:

About the heat-up over time, whether the windows of a vehicle are locked or partially open makes very little difference. In both situations, in an internal temperature of a vehicle, even at an outside temperature of only 72 ° F, it may exceed approximately 40 ° F within one hour. This happens mainly due to the greenhouse effect that is the heat inside the car is trapped and not allowed to escape. Thus, raising the temperature of the vehicle.

3 0
3 years ago
How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for a
Luba_88 [7]

Answer:

6

Explanation:

We are given that

\theta=2.12^{\circ}

Slid width,a=0.110 mm=0.11\times 10^{-3} m

1mm=10^{-3} m

Wavelength,\lambda=582 nm=582\times 10^{-9} m

1nm=10^{-9} m

We have to find the number of diffraction maxima are contained in a region of the Fraunhofer single-slit pattern.

asin\theta=\frac{2N+1}{2}\lambda

Using the formula

0.11\times 10^{-3}sin(2.12)=\frac{2N+1}{2}(582\times 10^{-9})

2N+1=\frac{0.11\times 10^{-3}sin(2.12)\times 2}{582\times 10^{-9}}

2N+1=13.98

2N=13.98-1=12.98

N=\frac{12.98}{2}\approx 6

Hence, 6 diffraction maxima are contained in a region of the Fraunhofer single-slit pattern

5 0
3 years ago
An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life
elena55 [62]

Answer:

The half-life is t_{1/2} = 1.005 h

Explanation:

Using the decay equation we have:

A=A_{0}e^{-\lambda t}

Where:

  • λ is the decay constant
  • A(0) the initial activity
  • A is the activity at time t

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that A = \frac{A_{0}}{2}

\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}

0.5=e^{-\lambda*1 h}

Taking the natural logarithm on each side we have:

ln(0.5)=-\lambda

\lambda=0.69 h^{-1}

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\lambda = \frac{ln(2)}{t_{1/2}}

t_{1/2} = \frac{ln(2)}{\lambda}

t_{1/2} = \frac{ln(2)}{0.69}

t_{1/2} = 1.005 h

I hope it helps you!

6 0
3 years ago
What is the difference between electric field and electrostatic field?
valentina_108 [34]
Semantically? An electric field does not have to be static while in electrostatics it's generally assumed that the electric field does not change or only changes so slowly that its rate of change doesn't matter. That's very different in electrodynamics where electric and magnetic field changes are always coupled.

7 0
3 years ago
Read 2 more answers
What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?
sergij07 [2.7K]
The answers to this question is the 4th one
5 0
3 years ago
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