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2 years ago

Magnet A doesn't have its poles labeled, but Magnet B has a clearly labeled north and south pole. If the

Physics

2 answers:

kondor19780726 [428]2 years ago

5 0

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

Read more on Brainly.com - brainly.com/question/14114321#readmore

dusya [7]2 years ago

4 0

Answer:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

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Where do subduction zones often occur

vodka [1.7K]

Subductions occur at convergent boundaries. Its where one tectonic plate moves under another.

-Steel jelly

4 0

2 years ago

A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

nexus9112 [7]

Answer:

$y=2.64m$

Explanation:

Given data

Ball one

mass m₁=3.0kg

velocity v₁=20 m/s

Ball second

mass m₂=2.0 kg

velocity v₂=12 m/s

First we need the speed of combined ball.Since the system conserves the linear momentum

$p_{i}=p_{f}\\m_{1}v_{1}+m_{2}v_{2}=m_{t}v_{t}$

So the combined velocity vt is:

$v_{t}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{t}}\\$

Since the two balls 1 and 2 are moving in opposite direction

$v_{t}=\frac{m_{1}v_{1}-m_{2}v_{2}}{m_{t}}\\$

Substitute the given values

$v_{t}=\frac{(3kg)(20m/s)-(2kg)(12m/s)}{(3+2)kg}\\ v_{t}=7.2 m/s$

We have the equation for motion with constant acceleration is given by:

$v^2=v_{o}^2+2g(y-y_{o})\\$

At initial position y₀=0 and vt=v-v₀

$v^{2}=v_{o}^2+2g(y-0)\\ y=\frac{v^2-v_{o}^2}{2g}\\ y=\frac{v_{t}^2}{2g}\\ y=\frac{(7.2m/s)^2}{2(9.8m/s^2)}\\ y=2.64m$

8 0

3 years ago

A 39.7 n object is in free fall. what is the magnitude of the net force which acts on the object? answer in units of n.

Vika [28.1K]

If there is no air resistance, the value would still be the same. So therefore, the answer is 39.7 N.
Supposing that there is an air resistance of 19.8 N.With a 19.8 N air resistance: ∑F = 39.7 N - 19.8 N = 19.9 N would be the net force. The important point here is that the force of gravity equivalent the weight of the object.

6 0

3 years ago

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r

madam [21]

Answer: 0.3872m

Explanation:

q= 100nC --> 100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

$E= K\frac{q}{r^{2} }$ --> $r=\sqrt{\frac{kq}{E} }$ Despejas "r"

Resuelves

<h3> $r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9} C)}{6000N/C} }$ (la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>

4 0

2 years ago

An astronaut orbits planet Y in her spaceship. To remain in orbit at 410km above the planet's center, she maintains a speed of 6

choli [55]

Formula for orbital speed, v = √(GM/R)

Where G is the universal gravitational constant, M = Central Mass,

R = Distance between centers of Mass.

Given. v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²

68 = √(GM/R)

68 = √(6.674 * 10⁻¹¹ * M/410000)

68² = (6.674 * 10⁻¹¹ * M)/410000

(68² * 410000) / 6.674 * 10⁻¹¹ = M

2.84 × 10¹⁹ = M

Mass of Planet Y = 2.84 × 10¹⁹ kg

3 0

2 years ago