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3 years ago

Magnet A doesn't have its poles labeled, but Magnet B has a clearly labeled north and south pole. If the

Physics

2 answers:

kondor19780726 [428]3 years ago

5 0

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

Read more on Brainly.com - brainly.com/question/14114321#readmore

dusya [7]3 years ago

4 0

Answer:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole

Explanation:

D: The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole because

1) opposite poles attract each other

2) similar poles repel each other

3)magnetic lines of force start at the north pole and end at the south pole

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How do you find the number of neutrons

sammy [17]

the mass number minus the atomic number

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3 years ago

A loop of area 0.100 m² is oriented at a 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0 degree

MatroZZZ [7]

The resulting change in the magnetic flux is =0.013Wb

what is magnetic flux?

Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area

Given:

At degree =15.5°,magnetic flux=magnetic field=0.500T

At degree=45.0°, magnetic field=0.500T

Magnetic flux=magnetic field ×Area×cos(angle)

magnetic flux (1) = 0.500×0.1×cos(15.5)

= 0.048

magnetic flux (2) = 0.500×0.1×cos(45)

=0.035

Resulting change in flux = 0.048-0.035

= 0.013Wb

learn more about magnetic flux from here: brainly.com/question/28179515

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8 0

2 years ago

A proton with a speed of 3.2 x 106 m/s is shot into a region between two plates that are separated by a distance of 0.23 m. As t

harina [27]

Answer:

<h2>The magnitude of the magnetic is 0.145 T</h2>

Explanation:

Given :

Speed of proton $v = 3.2 \times 10^{6}\frac{m}{s}$

Mass of proton $m = 1.67 \times 10^{-27}$ Kg

The force on the proton in magnetic field is given by,

$F = q (v \times B)$

$F = qvB \sin \theta$

But $\sin 90 = 1$ (∵ Force is perpendicular to the velocity so $\theta = 90$ )

$F = qvB$

When particle enter in magnetic field at the angle of 90° so particle moves in circle

So force is given by,

$F = \frac{mv^{2} }{r}$

Where $r =$ radius but in our case 0.23 m, $q = 1.6 \times 10^{-19}$ C

By comparing above two equation,

$B = \frac{mv}{qr}$

$B = \frac{1.67 \times 10^{-27} \times 3.2 \times 10^{6} }{1.6 \times 10^{-19} \times 0.23 }$

$B = 0.145$ T

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3 years ago

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andrezito [222]

A: Human Body

C is wrong because they don’t have the tools to test it on another planet

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