Use the results of Prob. 5–82 for plane strain near the tip with u 5 0 and n 5 13. If the yieldstrength of the plate is Sy, what
is s1 when yield occurs?(a) Use the distortion-energy theory.(b) Use the maximum-shear-stress theory. Using Mohr’s circles, explain your answer
1 answer:
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Answer:
Answer with Explanation is in the following attachments.
Explanation:
Answer:
W= 8120 KJ
Explanation:
Given that
Process is isothermal ,it means that temperature of the gas will remain constant.
T₁=T₂ = 400 K
The change in the entropy given ΔS = 20.3 KJ/K
Lets take heat transfer is Q ,then entropy change can be written as
Now by putting the values
Q= 20.3 x 400 KJ
Q= 8120 KJ
The heat transfer ,Q= 8120 KJ
From first law of thermodynamics
Q = ΔU + W
ΔU =Change in the internal energy ,W=Work
Q=Heat transfer
For ideal gas ΔU = m Cv ΔT]
At constant temperature process ,ΔT= 0
That is why ΔU = 0
Q = ΔU + W
Q = 0+ W
Q=W= 8120 KJ
Work ,W= 8120 KJ