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emmainna [20.7K]
3 years ago
8

why is the meteor crater in arizona still visible when most impact craters created by meteorites hitting earth are not

Physics
2 answers:
damaskus [11]3 years ago
8 0
Good question. The Arizona impact location is very, very, unique. The crater was the Bigger than Cuba when it first struck. Due to sedimentary drop off its size is slowly decaying. It is currently about the size of 2-3 Carnival cruise ships.
joja [24]3 years ago
4 0

Answer:

The meteor crater in Arizona is still visible  due to the sedimentary nature of the materials present, mainly limestone, and the total absence of lava in the zone.

Most of the craters created by other meteorites that have collided with the earth are not visible at present because they were smaller and also impacted in areas where the soil materials were more compact and firm.

Explanation:

It is estimated that the impact produced by the crater 50,000 years ago, and was caused by an nickel-iron meteorite about 50 m long traveling at an approximate speed of 12 km/sec.  The impact created a temperature so extraordinarily high that it vaporized or melted all the rocks in the surrounding crust.

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Urippe Went to start his lawnmower and was having trouble. At the same moment, Uwi was starting her identical lawnmower in the y
Ivan

Answer:

As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm

350 rev/min = 350(2π) / 60 = 36.652 rad/s

36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>

a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>

a =  αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>

I am GUESSING that we are supposed to model these mowers as a uniform disk

  τ = Iα

FR = (½mr²)α

  F = mr²α/2R

Urippe's pull  = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>

Usi's pull =        (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>

L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s  down</u>

using the right hand rule

8 0
3 years ago
In the graph above, what is the instantaneous speed of the object after the first five seconds?
alexdok [17]

Answer:

D) 25 m/s

Explanation:

In order to solve this problem we must use the following kinematics equation.

v_{f} =v_{i} +(a*t)\\

where:

Vf = final speed [m/s]

Vi = initial speed = 0

a = acceleration = 5[m/s^2]

t = time = 5[s]

After 5 seconds the acceleration is equal to 5 [m/s^2]

Now replacing the values in the equation:

Vf = 0 + (5*5)

Vf = 25[m/s]

8 0
3 years ago
An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad / s). if a particular disk is spun at 79
NeX [460]
(i) |α| = 235.6rad.s / 0.502s = 469 rad/s²
(ii) tang a = α*r = 469rad/s² * 0.12m / 2*11 = 2.56 m/s²
4 0
3 years ago
two ice skaters push each other, and move in opposite directions. the mass of one is 75 kg, and his speed is 2 m/s. if the mass
sattari [20]

momentum conservation

75x2 = 30 x her speed

75x2/30=150/30=5m/s

7 0
3 years ago
3. A model rocket takes 0.05 seconds to speed up from rest to its maximum velocity of 80 m/s.
nikklg [1K]

Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}

Where Vf is the final velocity of the object, (in our case 80 m/s)

Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)

and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.

Therefore we have:

a = \frac{80 m/s - 0 m/s}{0.05 sec} = 1600 \frac{m}{s^2}

Notice that the units of acceleration in the SI system are \frac{m}{s^2} (meters divided square seconds)

7 0
3 years ago
Read 2 more answers
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