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3 years ago

Evaluate 10 to the 7th

Mathematics

2 answers:

Vesna [10]3 years ago

7 0

Answer:

Answer is 10,000,000

Step-by-step explanation:

Calculate 10^7 by plugging it into a calculator

Olenka [21]3 years ago

5 0

Ya came to the right place! Its 10,000,000 fam

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Are all whole numbers counting numbers

lisov135 [29]

No, because zero is a whole number, but not a counting number.

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4 years ago

A runner is running a 10 km race. it takes her 17.5 minutes to reach the 2.5 km mark. at that rate, how long will it take her to

cluponka [151]

First find the unit rate. Do 17.5/2.5 and you get 7. Next just multiply that by 10 and voila. It takes her 70 minutes to run the whole race.

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3 years ago

Which ordered pair represents the plotted point on the graph?

mezya [45]

Hope this helps but the answer is A.(-5,2)

7 0

3 years ago

Read 2 more answers

Given the pre-image ABCD and the image after a dilation, A'B'C'D', what is true about the polygons? Check all that apply. The le

vazorg [7]

<h2>Answer </h2>

You should check the following:

The length of AB is 2

The length of A'B' is 3

The scale factor is $\frac{3}{2}$

<h2>Explanation</h2>

- To find the length of AB, we will use the distance formula:

$d(A,B)=|x_{1}-x_{2}|$

From the picture we can infer that $x_{1}=2$ and $x_{2}=4$ , so let's replace the values.

$d(A,B)=|2-4|$

$d(A,B)=|-2|$

$d(A,B)=2$

The length of AB is 2, so you should check the first answer

- To find the length of A'B', we will use the distance formula one more time:

From the picture we can infer that $x_{1}=3$ and $x_{2}=6$ , so let's replace the values.

$d(A',B')=|3-6|$

$d(A',B')=|-3|$

$d(A',B')=3$

Since the length of A'B' is 3, you should also check the second answer as well.

- In a transformation (in this case a dilation) the pre-image is the original shape and the image is the shape after the transformation.

Since the image is bigger than the pre-image, the third answer is false.

- Let $k$ be the scale factor

We know that the length of AB is 2 and we need to multiply that length by the scale factor to get length of A'B' i.e 3, so:

$2k=3$

$k=\frac{3}{2}$

Since the scale factor is $\frac{3}{2}$ , you should check the fourth answer as well.

- We already prove that the scale factor is $\frac{3}{2}$ , so the fifth answer is false.

5 0

4 years ago

Read 2 more answers

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}$

3 0

4 years ago