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Daniel [21]
3 years ago
12

What are two uses of ethanol?

Physics
1 answer:
Deffense [45]3 years ago
5 0
Gas and solar power I think
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The 6th harmonic of a pipe is open at both ends has a frequency of 732 Hz, on a day when the temperature is 10 degrees Celsius.
Stels [109]

Answer:

안녕하세요 우리는 어떻게 응을 하루?

Explanation:

이봐 우리는 오늘 응

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3 years ago
As a student studying in South Korea, what changes you think must be made in the education system to make it better?​
Zepler [3.9K]

Explanation:

studying hard is the only thing that could make the educational system better

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You are at the park with your little brother, when you notice a small merry-go-round with a radius that looks to be about 1.5 m.
Elodia [21]

Answer:

Explanation:

angle covered in one rotation = 2π radian

θ = ωt + 1/2 αt²

θ is angle rotated in time t with initial angular velocity of ω and angular acceleration α .

Putting the values

2π = 0 + 1/2 x α x 3²

α = 1. 4 radian / s²

linear acceleration =  α x r = 1.4 x 1.5 = 2.1 m / s².

Initial acceleration = 2.1 m /s²

final angular velocity = α t = 1.4 x 3 = 4.2 radian / s

linear velocity = 4.2 x 1.5 = 6.3 m /s

centripetal acceleration = v² / R = 6.3² / 1.5 = 26.46 m /s²

radian acceleration = 26.46 m /s

tangential acceleration = 2.1 m /s²

Total final acceleration = √ ( 26.46² + 2.1² )

= √ ( 700.13 + 4.41)

Final acceleration = 26.53 m / s²

7 0
3 years ago
The slope of the line on a speed-time graph tells the speed.
iren2701 [21]

From the choices provided, the better answer is ' T ' .

8 0
3 years ago
A ball is lodged in a hole in the floor near the outside edge of a merry-go-round that is turning at constant speed. Which kinem
dybincka [34]

Answer:

Explanation:

It is given that the ball is lodged in a hole in the floor of merry-go-round that is running at a constant speed.

Now the ball is moving a vertical circular motion  

The position of the ball changes w.r.t to the center as it moves in a circular path i.e. vectorially it changes but its magnitude will remain the same.  

The velocity of the ball is the same as merry-go-round so its magnitude remains the same but its direction will change continuously.

As the ball is moving in a circular path so a centripetal acceleration will acts towards the center so its value will be continuously changing.

3 0
3 years ago
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