Answer:
neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C
Explanation:
ni change eq.
N2O4 1 1 - x 0.8154.....P = 1 atm; T = 25°C
NO2 0 0 + x x
∴ x = neq = Peq.V / R.T.....ideal gas mix
if P = 0.5 atm, T = 25°C; assuming: V = 1 L
⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))
⇒ x = neq = 0.0205 mol
⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol
Answer:
It is called tempering. Its tensile strength may reduce but it will become more rigid and hard to break compared to the original metal.
Explanation:
( Source : Quora )
Answer:
No, compound A and B are not the same compound
Explanation:
According to the law of definite proportion "every chemical compound contains fixed and constant proportions (by mass) of its constituent elements." (Encyclopedia Britannica)
We can see in the question that the ratio of flourine to sulphur in compound A is 1.18 while the ratio of flourine to sulphur in compound B is 2.37.
The two chemical compounds do not contain a fixed proportion by mass of their constituent elements therefore, they can not be same compound according to the law of definite proportions.
Answer:
Option A. 6.75 (6.20/85.6)
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 6.2cm³
Initial concentration (C1) = 6.75M
Final volume (V2) = 85.6cm³
Final concentration (C2) =.?
The final concentration can be obtained by using the dilution formula as show below:
C1V1 = C2V2
6.75 x 6.2 = C2 x 85.6
Divide both side by 85.6
C2 = (6.75 x 6.2) /85.6
C2 = 6.75 (6.2 / 85.6).
<h2>
Answer:</h2>
Option B. Potassium(K).
<h2>
Explanation:</h2>
Electronic configuration of the given elements are:
- Ca - [Ar] 4s²
- K - [Ar] 4s¹
- B - [He] 2s2 2p1
- Kr - [Ar] 3d¹⁰4s²4p⁶
- Krypton(K) have 36 electrons and it is a noble gas and hence all of its shells are completely filled with electrons and hence it will never loose electrons in normal conditions.
- Boron(B) have 5 electrons and 3 electrons in its outer shell. In order to attain a stable configuration it will loose 3 electrons and it is difficult to loose 3 electrons at a time for an atom.
- Calcium(Ca) have 20 electrons and 2 electrons in its outermost shell, in order to attain a stable configuration it will loose 2 electrons. it is quite difficult but easier than Boron.
- Potassium(K) have 21 electrons and 1 electron in its outermost orbit and in order to attain a stable configuration it will loose 1 electron. It is much easier to donate 1 electron than 2 or 3 electrons.
Result: Potassium will loose an electron most easily from the given elements.
