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Harman [31]
3 years ago
8

When Sulphur dioxide reacts with water the product formed is

Chemistry
2 answers:
rosijanka [135]3 years ago
7 0

Answer:

2 .Sulphurous acid

Explanation:

Sulphur dioxide can dissolve in water to form Sulfurous acid(H2SO3). sulphurous acid is weackly dibasic acid. sulphur dioxide is a major component of acid rain since it mixes with vapour in the atmosphere reacting to produce H2So4 .

Svetllana [295]3 years ago
3 0

Answer:

Sulphuric acid

Explanation:

Sulphuric acid is a major component of acid rain since it mixes with water vapour in the atmosphere, reacting to produce Sulphuric acid.

Hope that helped...

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If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?
SpyIntel [72]

Answer: 1.57 M

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}

7 0
2 years ago
How many chiral centers does clavulanic acid have?
VikaD [51]

Answer:

Clavulanic acid has two (2) chiral centers.

Explanation:

A chiral center is a center (usually carbon) with four different substituents.

The structure of clavulanic acid is shown in the attachment below.

Consider the labeled diagram in the attachment,

Carbon A is not a chiral carbon because it has two hydrogen atoms attached to it

Carbon B is not a chiral carbon because it has only three substituents

Carbon C is a chiral carbon because it has four different substituents

Carbon D is a chiral carbon because it has four different substituents

Carbon E is not a chiral carbon because it has only three atoms directly attached to it

Carbon F is not a chiral carbon because it has only three atoms directly attached to it

Carbon G is not a chiral carbon because it has two hydrogen atoms attached to it

Carbon H is not a chiral carbon because it has only three substituents

Then, only carbons C and D are chiral carbons.

Hence, clavulanic acid have two (2) chiral centers.

7 0
3 years ago
C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What
umka21 [38]
The  molar mass  of  the unknown  compound  is   calculated   as   follows

let the unknown  gas be represented by   letter  Y

Rate of C2F4/  rate of  Y  = sqrt of   molar  mass of gas Y/ molar mass of  C2F4

 =  (4.6  x10^-6/ 5.8  x10^-6)  = sqrt  of  Y/ 100

remove  the  square  root  sign  by  squaring  in both  side

(4.6  x  10^-6 / 5.8  x10^-6)^2 =  Y/100

= 0.629 =Y/100

multiply  both side  by  100

Y=  62.9 is  the molar  mass of unknown  gas



5 0
3 years ago
A 2.5 mg sample of magnesium powder is ignited with 2 mg oxygen in a sealed container. All of the magnesium is consumed and 4.15
lys-0071 [83]

Answer:

Total mass of the reactant = 2+2.5 =4.5 mg

Total mass of product = 4.15 mg

therefore, mass of unreacted oxygen = 4.50-4.15 = 0.35 g

7 0
4 years ago
What is equal to the number of particles in 36 grams of carbon-12?
HACTEHA [7]

Answer:

3 moles

Explanation:

To solve this problem we will  use the Avogadro numbers.

The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance.  According to this,

1.008 g of hydrogen = 1 mole =  6.022×10²³  atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 =  2 mole

36 g of C-12 = 3 mole

So 3 moles of C-12 equals to the number of particles in 36 g of C-12.

4 0
3 years ago
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