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Harman [31]
3 years ago
8

When Sulphur dioxide reacts with water the product formed is

Chemistry
2 answers:
rosijanka [135]3 years ago
7 0

Answer:

2 .Sulphurous acid

Explanation:

Sulphur dioxide can dissolve in water to form Sulfurous acid(H2SO3). sulphurous acid is weackly dibasic acid. sulphur dioxide is a major component of acid rain since it mixes with vapour in the atmosphere reacting to produce H2So4 .

Svetllana [295]3 years ago
3 0

Answer:

Sulphuric acid

Explanation:

Sulphuric acid is a major component of acid rain since it mixes with water vapour in the atmosphere, reacting to produce Sulphuric acid.

Hope that helped...

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Think about agriculture research which of the following statements is accurate?
irina [24]

A.genetic modification of food helps it grow more easily in certain areas

Explanation:

The statement genetic modification of food helps it grow more easily in certain areas is a form of agricultural research that is very accurate.

Genetically modifying food is common practice in order to encourage desirable and sustainable traits in plant species.

  • Drought resistant breeds can tolerate a much lower level of water in some specific areas.
  • Disease resistant breeds are more adapted to outbreaks of plant epidemics.
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KClO3 ---> KCl + O2 Balance the decomposition chemical reaction. A) KClO3 ---> KCl + O2 B) 2KClO3 ---> KCl + 3O2 C) 2KC
Damm [24]
And the answer is C.
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Which of the following cannot have hydrogen bonds? Select one: A. NH3 B. H2O C. HF D. CH3NH2 E. Which of the following cannot ha
noname [10]

Answer:

E. HCl

Explanation:

Cl atom does not have enough electronegativity to make enough positive charge on H.

3 0
3 years ago
How to calculate IMA
Cloud [144]
Using IMA is used in Engineering, but there is a simple rhyme I use called IMA Deer. IMA=De/Dr

7 0
3 years ago
Suppose that you add 28.8 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a
Brrunno [24]

Answer:

THE MOLAR MASS OF THE UNKNOWN COMPOUND IS 242.02 g/mol.

Explanation:

First:

Calculate the change in freezing point:

          Freezing point of pure benzene = 5.5°C

Change in temperature = 5.5 - 3.06 = 2.44 °C

Second:

Using the formula:

Δt = i Kf m

Let's assume i = 1

Kf = 5.12 °C/m

M = x / 0.250 kg of benzene

Then we can calculate x which is the molarity

Re-arranging the formula, we have:

m = Δt / i Kf

x / 0.250 = 2.44 / 1 * 5.12

x = 2.44 * 0.250 / 5.12

x = 0.61 / 5.12

x = 0.119 M

Since it is well known that molarity is the mass of a substance divided by its molar mass. We can then calculate the molar mass.

Molar mass = Mass / molarity

Molar mass = 28.8 g / 0.119 M

Molar mass =242.02 g/mol

Hence, the molar mass of the unknown molecular compound is 242.02 g/mol.

4 0
3 years ago
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