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slavikrds [6]
2 years ago
13

Draw an electron

Chemistry
1 answer:
butalik [34]2 years ago
3 0

Answer:

 . .

: Ne :

  . .

Explanation:

Let's take Neon as our example. In the Lewis dot structure, each dot corresponds to an electron in the valence shell of the atom. All atoms like to have a full valence shell. By the octet rule, this means that they need 8 electrons total to be electronically satisfied. Noble gases all have a full valence shell in their natural state. This is why they are inert, as they do not need extra electrons to be electronically satisfied.

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Name the following bases.
zheka24 [161]

Answer:

1

Explanation:

Ferric Hydroxide

3. 1

Fe. (OH)

Fe(OH)3

6 0
3 years ago
A compound contains 6.0 g of carbon and 1.0 g of hydrogen and has a molar mass of 42.0 g/mol.
makvit [3.9K]

Answer:

%C = 85.71 wt%; %H = 14.29 wt%; Empirical Formula => CH₂; Molecular Formula => C₃H₆

Explanation:

%Composition

Wt C = 6 g

Wt H = 1 g

TTL Wt = 6g + 1g = 7g

%C per 100wt = (6/7)100% = 85.71 wt%

%H per 100wt = (1/7)100% = 14.29 wt % or, %H = 100% - %C = 100% - 85.71% = 14.29 wt% H

What you should know when working empirical formula and molecular formula problems.

Empirical Formula=> <u>smallest</u> whole number ratio of elements in a compound

Molecular Formula => <u>actual</u> whole number ratio of elements in a compound

Empirical Formula Weight x Whole Number Multiple = Molecular Weight

From elemental %composition values given (or, determined as above), the empirical formula type problem follows a very repeatable pattern. This is ...

% => grams => moles => ratio => reduce ratio => empirical ratio

for determination of molecular formula one uses the empirical weight - molecular weight relationship above to determine the whole number multiple for the molecular ratios.

Caution => In some 'textbook' empirical formula problems, the empirical ratio may contain a fraction in the amount of 0.25, 0.50 or 0.75. If such an issue arises, multiply all empirical ratio numbers containing 0.25 and/or 0.75 by '4'  to get the empirical ratio and multiply all empirical ration numbers containing 0.50 by '2' to get the final empirical ratio.

This problem:

Empirical Formula:

Using the % per 100wt values in part 'a' ...

              %     =>         grams                 =>                 moles

%C => 85.71% => 85.71 g* / 100 g Cpd => (85.71 / 12) = 7.14 mol C

%H => 14.29% => 14.29 g / 100 g Cpd => (14.29 / 1) = 14.29 mol H

=> Set up mole Ratio and Reduce to Empirical Ratio:

mole ratio C:H =>  7.14 : 14.29

<u>To reduce mole values to the smallest whole number ratio,  divide all mole values by the smaller mole value of the set.</u>

=> 7.14/7.14 : 14.29/7.14 => Empirical Ration=> 1 : 2

∴ Empirical Formula => CH₂

Molecular Formula:

(Empirical Formula Wt)·N = Molecular Wt => N = Molecular Wt / Empirical Wt

N = 42 / 14 = 3 => multiply subscripts of empirical formula by '3'.

Therefore, the molecular formula is C₃H₆

3 0
3 years ago
What is the difference between luster and dull
Aleks04 [339]

<h2>Explanation:</h2><h2> </h2>

Luster means Shiny. Dull means simple and not full of detail. Hope this helps!Please Rate Brainiest!

-Aslina

3 0
3 years ago
What is the most viable solution for climate change
Korvikt [17]

Answer:

The Only Viable Solution: A New Moon Shot

The electric light bulb didn't appear from efforts to develop better candles or telling people to use less light.

3 0
4 years ago
Calculate the atomic mass of silver if 13 out of 25 atoms are silver-107 and 12 out of 25 are silver-109
nekit [7.7K]

From,

RAM=element×its relative abudance/total abudance

=((107×13)+(12×109))/25

The answer is=107.96

3 0
3 years ago
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