Producer. Hope this helps!
The reaction will produce 12.1 g Ag₂S.
<em>Balanced equation</em> = 2Ag + S ⟶ Ag₂S
<em>Mass of Ag₂S</em> = 10.5 g Ag × (1 mol Ag/107.87 g Ag) × (1 mol Ag₂S/2 mol Ag)
× (247.80 g Ag₂S/1 mol Ag₂S) = 12.1 g Ag₂S
Answer:
1813.74g
Explanation:
Given parameters:
Number of moles of radon = 8.17moles
Unknown:
Mass of radon = ?
Solution:
To solve this problem, we use the expression below:
Number of moles =
Molar mass of radon = 222g/mol
Now insert the parameters and solve;
Mass of radon = Number of moles x molar mass
= 8.17 x 222
= 1813.74g
C = 4 mol/l
v = 0.5 l
n(NaCl)=cv
n(NaCl) = 4 mol/l · 0.5 l = 2 mol
2 moles of NaCl must be dissolved
Answer:
32
Explanation:
0.56dm of gas has 0.8g
22.4dm of gas Z has a mass of 22.4/0.56X0.8
the relative molecular mass of gas Z is 32