Answer:
Explanation:
a. The equation of Lorentz transformations is given by:
x = γ(x' + ut')
x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.
x' = 0
t' = 5.00 s
u =0.800 c,
c is the speed of light = 3×10⁸ m/s
Then,
γ = 1 / √ (1 - (u/c)²)
γ = 1 / √ (1 - (0.8c/c)²)
γ = 1 / √ (1 - (0.8)²)
γ = 1 / √ (1 - 0.64)
γ = 1 / √0.36
γ = 1 / 0.6
γ = 1.67
Therefore, x = γ(x' + ut')
x = 1.67(0 + 0.8c×5)
x = 1.67 × (0+4c)
x = 1.67 × 4c
x = 1.67 × 4 × 3×10⁸
x = 2.004 × 10^9 m
x ≈ 2 × 10^9 m
Now, to find t we apply the same analysis:
but as x'=0 we just have:
t = γ(t' + ux'/c²)
t = γ•t'
t = 1.67 × 5
t = 8.35 seconds
b. Mavis reads 5 s on her watch which is the proper time.
Stanley measured the events at a time interval longer than ∆to by γ,
such that
∆t = γ ∆to = (5/3)(5) = 25/3 = 8.3 sec which is the same as part (b)
c. According to Stanley,
dist = u ∆t = 0.8c (8.3) = 2 x 10^9 m
which is the same as in part (a)
The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.
<h3>Resistance of the circuit</h3>
For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.
![Z= R\sqrt{2} \\\\R = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms](https://tex.z-dn.net/?f=Z%3D%20R%5Csqrt%7B2%7D%20%5C%5C%5C%5CR%20%20%3D%20%5Cfrac%7BZ%7D%7B%5Csqrt%7B2%7D%20%7D%20%5C%5C%5C%5CR%20%3D%20%5Cfrac%7B1000%7D%7B%5Csqrt%7B2%7D%20%7D%20%3D%20707.1%20%5C%20ohms)
<h3>Resonant frequency</h3>
![f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%20%5Csqrt%7BLC%7D%20%7D%20%5C%5C%5C%5C6000%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%20%5Csqrt%7BLC%7D%20%7D%20%5C%5C%5C%5C2%5Cpi%286000%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%20%7D%20%5C%5C%5C%5C%5Csqrt%7BLC%7D%20%3D%20%5Cfrac%7B1%7D%7B2%5Cpi%20%286000%29%7D%20%5C%5C%5C%5CLC%20%3D%20%28%5Cfrac%7B1%7D%7B2%5Cpi%20%286000%29%7D%29%5E2%5C%5C%5C%5CLC%20%3D%207.034%20%5Ctimes%2010%5E%7B-10%7D%20%5C%5C%5C%5C%20C%20%3D%20%5Cfrac%7B7.034%20%5Ctimes%2010%5E%7B-10%7D%20%7D%7BL%7D%20---%281%29)
<h3>At driven frequency</h3>
![X_l- X_c = R\\\\\omega L - \frac{1}{\omega C} = 707.1\\\\2\pi f L - \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\](https://tex.z-dn.net/?f=X_l-%20X_c%20%3D%20R%5C%5C%5C%5C%5Comega%20L%20-%20%5Cfrac%7B1%7D%7B%5Comega%20C%7D%20%20%3D%20707.1%5C%5C%5C%5C2%5Cpi%20f%20L%20-%20%20%5Cfrac%7B1%7D%7B2%5Cpi%20fC%7D%20%3D%20707.1%5C%5C%5C%5C2%5Cpi%20%288000%29%20L%20-%20%5Cfrac%7B1%7D%7B2%5Cpi%20%288000%29%20C%20%7D%20%3D%20707.1%5C%20%5C%20--%282%29%5C%5C%5C%5C)
<em>solve 1 and 2 together</em>
![2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H](https://tex.z-dn.net/?f=2%5Cpi%288000%29%20L%20-%20%5Cfrac%7BL%7D%7B2%5Cpi%20%288000%29%287.034%20%5Ctimes%2010%5E%7B-10%7D%29%7D%20%3D%20707.1%5C%5C%5C%5C50272L%20-%2028279.48L%20%3D%20707.1%5C%5C%5C%5CL%20%3D%200.032%20%5C%20H)
Learn more about impedance of RLC circuit here: brainly.com/question/372577
Copper is the second best known electrical conducting substance. The first best one is silver. We almost always use copper because silver costs too much.
The speed of the combined carts after the collision is 0.25 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
where:
is the mass of the first cart
is the initial velocity of the first cart
is the mass of the second cart
is the initial velocity of the second cart
is the final combined velocity of the two carts
Re-arranging the equation and substituting the values, we find: the final velocity:
![v=\frac{m_1 u_1}{m_1+m_2}=\frac{(1.0)(0.50)}{1.0+1.0}=0.25 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm_1%20u_1%7D%7Bm_1%2Bm_2%7D%3D%5Cfrac%7B%281.0%29%280.50%29%7D%7B1.0%2B1.0%7D%3D0.25%20m%2Fs)
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