Answer:
3.47km/h with a direction of 67.8 degrees north of west.
Explanation:
First we need to calculate the displacement on the X axis, so:
then on the Y axis:
The magnitud of the displacement is given by:
and the angle:
that is 67.8 degrees north of west.
Apparent magnitude means how bright a star APPEARS to us on Earth. It can be affected by ...
... how bright the star really is
... how far the star is from us
... how much gas and dust is between us
... how much of the star's total output is in visible light
Hey! If this is on big ideas get a app called “Slader” It has answers to all math problems just like up the book you use > save it > type in the section you are doing > and look for the problems you are doing.
Answer:
i. 0.34
ii. 0.4
iii. 1700 w/m²
iv. 2211.36 w/m²
Explanation:
Given that
Irradiation of the plate, G = 2500 w/m²
Reflected rays, p = 500 w/m²
Emissive power, E = 1200 w/m²
See attachment for calculations
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules.
Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
