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Ivahew [28]
3 years ago
15

A ball is thrown into the air at an angle. What is the instantaneous velocity of this ball in the vertical direction at the top

of its flight?
Physics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

0 m/s

Explanation:

At the instant the ball reaches the top of its flight, it isn't moving up or down.  So the vertical component of the instantaneous velocity is 0 m/s.

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As a skydiver with a mass of 54 kg falls toward the Earth, she accelerates at 9.8 m/s2. What is the force of
Kisachek [45]

Answer:

B. The force due to gravity is 530 N. The force of air resistance is less than the force due to gravity.

Explanation:

4 0
3 years ago
Materials having resistance changes as voltage or current varies are called:
Fofino [41]
I believe they are called nonohmic materials. According to ohms law the current trough a current carrying conductor is directly proportional to the potential difference (voltage) at a constant resistance.  Non-ohmic conductors or materials are those materials that do not obey the ohms law, their resistance increases as the current increases. Ohmic materials are those that obeys the ohms law such that the voltage and current are proportional- doubling the potential difference doubles the current.
8 0
3 years ago
Unpolarized light whose intensity is 1.46 W/m2 is incident on the polarizer in the drawing. (a) What is the intensity of the lig
Serhud [2]

Answer:

0.73 W/m²

0.2522 W/m²

Explanation:

I_0 = Unpolarized light = 1.46 W/m²

\theta = Analyzer angle = 54°

Light through first filter

I_1=\frac{I_0}{2}\\\Rightarrow I_1=\frac{1.46}{2}\\\Rightarrow I_1=0.73\ W/m^2

The intensity of the light leaving the polarizer is 0.73 W/m²

After passing through analyzer

I=I_1cos^2\theta\\\Rightarrow I=0.73\times cos^2(54)\\\Rightarrow I=0.2522\ W/m^2

The intensity of the light that reaches the photocell is 0.2522 W/m²

6 0
3 years ago
A point charge q1=+2.40μC is held stationary at the origin. A second point charge q2=−4.30μC moves from the point x=0.125m , y=0
algol [13]

Answer:

Explanation:

Potential energy of a pair of charges

= k q₁q₂ /r₁₂

At r₁₂ = .125 m

= - 9 x 10⁹ x 2.4 x 4.3 x 10⁻¹² / .125

= - 743 x 10⁻³J

At r₁₂ = √2 x .275 m

- 9 x 10⁹ x 2.4 x 4.3 x 10⁻¹² / √2 x .275

= - 238.85  x 10⁻³J

= 239 x 10⁻³ J

Change = - 238.85  x 10⁻³ +743 x 10⁻³

= 504.15 x 10⁻³ J

B )

Work done by electric force will be same but in negative sign

= - 504.15 x 10⁻³ J

= - 504 x 10⁻³ J

3 0
3 years ago
A young man sets a goal to compete in a marathon in two weeks. He started training last week by exercising three to four times a
gogolik [260]
The aspect of his fitness program that could keep the young man from achieving his goal would potentially be the exercise with his friend. His friend could be a hindrance to his motivation to do more or to continue. If he's so attached with exercising with his friend and his friend decides to stop, then he would probably lose motivation.
7 0
3 years ago
Read 2 more answers
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