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daser333 [38]
3 years ago
8

A young man sets a goal to compete in a marathon in two weeks. He started training last week by exercising three to four times a

week with his friend. After each training session he writes his daily experiences to assess problems that may hinder his achievements. What aspect of his fitness program could keep him from achieving his goal?
Physics
2 answers:
gogolik [260]3 years ago
7 0
The aspect of his fitness program that could keep the young man from achieving his goal would potentially be the exercise with his friend. His friend could be a hindrance to his motivation to do more or to continue. If he's so attached with exercising with his friend and his friend decides to stop, then he would probably lose motivation.
Crazy boy [7]3 years ago
6 0

Explanation:

The marathon is set to start in two weeks and the young man starts his training from the last week exercising three to four times a week. So this requires a lot of strength and a lot of hard work. So as there is only two weeks time for him, he needs to train regularly in order to increase his stamina and strength to run and win the marathon. He should remain hydrated all the time so that his body functions properly and does not affect his health. He should work on his speed and stamina and exercise regularly to keep him fit and be able compete in the marathon.

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RSB [31]

Answer: hello your question is incomplete below is the missing part

A spherical cavity is hollowed out of the interior of a neutral conducting sphere. At the center of the cavity is a point charge, of positive charge q.

answer:

- q

Explanation:

Since the spherical cavity was carved out of a neutral conducting sphere hence the electric field inside this conductor = zero

given that there is a point charge +q at the center of the spherical cavity hence for the electric field inside the conductor to be = zero the total surface charge qint on the wall of the cavity will be -q

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3 years ago
A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the i
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Answer:

451.13 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁)............... Equation 1

Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.

Make c the subject of the equation

c = Q/m(t₂-t₁).............. Equation 2

From the question,

Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C

Substitute these values into equation 2

c = 1500/[0.133(45-20)]

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2 years ago
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Answer:

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Answer:

It is calculated by dividing Resistance, R, by Inductive reactance, XL.

Explanation:

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Q factor of a resonance parallel circuit,

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