Toughest push and it’s didushehsuuahsydusuays
Answer:
7500 m
Explanation:
The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.
We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so
d = 2L
In a time of
Electromagnetic waves travel in a vacuum at the speed of light, which is equal to
Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:
(1)
where
, where L is the distance between the radar and the object
Re-arranging eq(1) and substituting, we find L:
Answer:
a = - 5 m/s²
Explanation:
The acceleration of the ball can be found by using the general formula of acceleration as follows:
where,
a = acceleration of ball = ?
ΔV = change in velocity = Final Velocity - Initial Velocity
ΔV = - 0.4 m/s - 0.6 m/s = -1 m/s
Δt = time of contact with the wall = 0.2 s
Therefore, using the values in equation, we get:
Therefore, the correct option is:
<u>a = - 5 m/s²</u>
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