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gizmo_the_mogwai [7]
3 years ago
12

Which statement accurately describes what happens when water turns to ice in terms of energy? A.The water absorbs which causes c

hemical bonds to form changing water into ice.
B. The water absorbs energy which causes the water molecules to have more kinetic and potential energy, changing their configuration from a liquid to a solid.
C. The water releases energy which causes the water molecules to have less kinetic and potential energy changing their configuration from liquid to solid.
D. The water releases energy which causes Chemical bonds to form changing water into ice
Physics
2 answers:
Marina CMI [18]3 years ago
6 0
The answer is D because water has less kinetic energy so the particles stay closer together
Liono4ka [1.6K]3 years ago
3 0

Answer: Option (D) is the correct answer.

Explanation:

When water turns into ice then energy is released by water molecules. As a result, there will be a decrease in kinetic energy of water molecules.

Therefore, potential energy increases and molecules come closer to each other. Hence, state of water changes from liquid to solid.

Thus, we can conclude that out of the given options, the statement water releases energy which causes chemical bonds to form changing water into ice accurately describes what happens when water turns to ice in terms of energy.

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Three equal point charges, each with charge 1.45 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
LUCKY_DIMON [66]

Answer:

U = 80.91 J

Explanation:

In order to calculate the electric potential energy between the three charges you use the following formula:

U=k\frac{q_1q_2}{r_{1,2}}                  (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q1: q2 charge

r1,2: distance between charges 1 and 2.

For the three charges you have:

U_T=k\frac{q_1q_2}{r_{1,2}}+k\frac{q_1q_3}{r_{1,3}}+k\frac{q_2q_3}{r_{2,3}}           (2)

You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:

q = 1.45μC = 1.45*10^-6C

r = 0.700mm = 0.700*10^-3m

U_T=3k\frac{q^2}{r}=3(8.98*10^9Nm^2/C^2)\frac{(1.45*10^{-6}C)}{0.700*10^{-3}m}\\\\U_T=80.91J

The electric potential energy between the three charges is 80.91 J

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Explanation:

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