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gizmo_the_mogwai [7]
3 years ago
12

Which statement accurately describes what happens when water turns to ice in terms of energy? A.The water absorbs which causes c

hemical bonds to form changing water into ice.
B. The water absorbs energy which causes the water molecules to have more kinetic and potential energy, changing their configuration from a liquid to a solid.
C. The water releases energy which causes the water molecules to have less kinetic and potential energy changing their configuration from liquid to solid.
D. The water releases energy which causes Chemical bonds to form changing water into ice
Physics
2 answers:
Marina CMI [18]3 years ago
6 0
The answer is D because water has less kinetic energy so the particles stay closer together
Liono4ka [1.6K]3 years ago
3 0

Answer: Option (D) is the correct answer.

Explanation:

When water turns into ice then energy is released by water molecules. As a result, there will be a decrease in kinetic energy of water molecules.

Therefore, potential energy increases and molecules come closer to each other. Hence, state of water changes from liquid to solid.

Thus, we can conclude that out of the given options, the statement water releases energy which causes chemical bonds to form changing water into ice accurately describes what happens when water turns to ice in terms of energy.

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Juanita made an electromagnet by placing an iron bar inside a coil of wire and then running current through the wire. After awhi
swat32

Answer: Correct Ans is B

Explanation:

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3 years ago
Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume t
FromTheMoon [43]

Answer:

n= 16021.03 slaps

Explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒mc\Delta T= n\frac{1}{2}m_hv_h^2

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

1\times4180(76.66)= n\frac{1}{2}0.4\times10^2

n= 16021.03 slaps

8 0
3 years ago
A technician is diagnosing a car that had both front brake hoses replaced 5,000 miles ago. An inspection reveals that the right
Mamont248 [21]

Answer:

Option B

Technician B only is correct

Explanation:

Technician a is wrong because the rupture was not caused by switching DOT (Department of Transportation) 3 and DOT 4 Brake fluids. As a matter of fact both brake fluids are compatible with most vehicular systems, and to a certain extent they can be used interchangeably without any adverse effect.

Technician B on the other hand, gives a more accurate reason, since a twisted brake hose will definitely fail and rupture once enough force is applied to it, which is most likely the case of what happened considering the mileage it ran before rupturing. Within this mileage, it is very possible for the pressure on the already twisted brake hose to have been damaging it gradually before finally making it to rupture.

4 0
3 years ago
An Atwood machine is constructed using two
Tomtit [17]

Answer:

0.47 m/s²

Explanation:

Assuming the string is inelastic, m₃ will accelerate downward at a rate of -a, and m₄ will accelerate upward at a rate of +a.

Draw a four free body diagrams, one for each hanging mass and one for each wheel.

For m₃, there are two forces: weight force m₃g pulling down, and tension force T₃ pulling up.  Sum of forces in the +y direction:

∑F = ma

T₃ − m₃g = m₃(-a)

For m₄, there are two forces: weight force m₄g pulling down, and tension force T₄ pulling up.  Sum of forces in the +y direction:

∑F = ma

T₄ − m₄g = m₄a

For m₁, there are two forces: tension force T₃ pulling down, and tension force T pulling right.  Sum of the torques in the counterclockwise direction:

∑τ = Iα

T₃r₃ − Tr₃ = (m₁r₃²) (a/r₃)

T₃ − T = m₁a

For m₂, there are two forces: tension force T₄ pulling down, and tension force T pulling left.  Sum of the torques in the counterclockwise direction:

∑τ = Iα

Tr₄ − T₄r₄ = (m₂r₄²) (a/r₄)

T − T₄ = m₂a

We now have 4 equations and 4 unknowns.  Let's add the third and fourth equations to eliminate T:

(T₃ − T) + (T − T₄) = m₁a + m₂a

T₃ − T₄ = (m₁ + m₂) a

Now let's subtract the second equation from the first:

(T₃ − m₃g) − (T₄ − m₄g) = m₃(-a) − m₄a

T₃ − m₃g − T₄ + m₄g = -(m₃ + m₄) a

T₃ − T₄ = (m₃ − m₄) g − (m₃ + m₄) a

Setting these two expressions equal:

(m₁ + m₂) a = (m₃ − m₄) g − (m₃ + m₄) a

(m₁ + m₂ + m₃ + m₄) a = (m₃ − m₄) g

a = (m₃ − m₄) g / (m₁ + m₂ + m₃ + m₄)

Plugging in values:

a = (1.64 kg − 1.27 kg) (9.8 m/s²) / (2.5 kg + 2.3 kg + 1.64 kg + 1.27 kg)

a = 0.47 m/s²

4 0
3 years ago
A solid sphere is released from the top of a ramp that is at a height h1 = 2.30 m. It rolls down the ramp without slipping. The
Oksi-84 [34.3K]

Answer:

The horizontal distance d does the ball travel before landing is 1.72 m.

Explanation:

Given that,

Height of ramp h_{1}=2.30\ m

Height of bottom of ramp h_{2}=1.69\ m

Diameter = 0.17 m

Suppose we need to calculate the horizontal distance d does the ball travel before landing?

We need to calculate the time

Using equation of motion

h_{2}=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2h_{2}}{g}}

t=\sqrt{\dfrac{2\times1.69}{9.8}}

t=0.587\ sec

We need to calculate the velocity of the ball

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times(\dfrac{2}{5}mr^2)\times(\dfrac{v}{r})^2

K.E=\dfrac{7}{10}mv^2

Using conservation of energy

K.E=mg(h_{1}-h_{2})

\dfrac{7}{10}mv^2=mg(h_{1}-h_{2})

v^2=\dfrac{10}{7}\times g(h_{1}-h_{2})

Put the value into the formula

v=\sqrt{\dfrac{10\times9.8\times(2.30-1.69)}{7}}

v=2.922\ m/s

We need to calculate the horizontal distance d does the ball travel before landing

Using formula of distance

d =vt

Where. d = distance

t = time

v = velocity

Put the value into the formula

d=2.922\times 0.587

d=1.72\ m

Hence, The horizontal distance d does the ball travel before landing is 1.72 m.

8 0
3 years ago
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