Answer:
y₀ = 1020.3 m
Explanation:
This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.
y = y₀ + 
t - ½ g t²
when it reaches the ground its height is zero
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 14.43²
y₀ = 1020.3 m
Answer:
charge will be equal to 
Explanation:
We have given mass of the particle m = 1.45 gram = 0.00145 kg
Acceleration due to gravity 
Electric field E = 700 N/C
Electric force will be equal to 
, here q is charge and E is electric field
For particle to be stationary this force must be equal to force due to gravity , that is mg force
So qE = mg
So charge will be equal to
Answer:
163.35
__________________________________________________________
<u>We are given:</u>
Mass of the object (m) = 36.3 kg
Velocity of the object (v) = 3 m/s
<u>Kinetic Energy of the object:</u>
We know that:
Kinetic Energy = 1/2(mv²)
KE = 1/2(36.3)(3)² [replacing the variables with the given values]
KE = 18.15 * 9
KE = 163.35 Joules
Hence, the cart has a Kinetic Energy of 163.35 Joules
The color of light that a star emits is somewhat related to its age, whereas the color of light that we actually <em>observe</em> from a star is related to the speed at which it's moving with respect to us.
It’s gonna be Oxygen ....
