Answer: 1 inclined plane and box mover trolley
2 screw and drill
3 The axle, or rod and wheels
4 slides, ramps, and hills.
5 yes because they help the ball move quicker
6 i am not sure about this one)
Explanation:i do not know i am guessing
The wave length becomes shorter and the pitch becomes higher
At the "very top" of the ball's path, there's a tiny instant when the ball
is changing from "going up" to "going down". At that exact tiny instant,
its vertical speed is zero.
You can't go from "rising" to "falling" without passing through "zero vertical
speed", at least for an instant. It makes sense, and it feels right, but that's
not good enough in real Math. There's a big, serious, important formal law
in Calculus that says it. I think Newton may have been the one to prove it,
and it's named for him.
By the way ... it doesn't matter what the football's launch angle was,
or how hard it was kicked, or what its speed was off the punter's toe,
or how high it went, or what color it is, or who it belongs to, or even
whether it's full to the correct regulation air pressure. Its vertical speed
is still zero at the very top of its path, as it's turning around and starting
to fall.
Answer:
P = 5400[W]
Explanation:
We must use the following equation of kinematics to calculate the acceleration.
where:
Vf = final velocity = 9 [m/s]
Vo = initial velocity = 0 (starting from rest)
a = acceleration [m/s²]
t = time = 1.5 [s]
Now with this second equation of kinematics, we can determine the distance traveled.
where:
x= distance [m]
Now we must use Newton's second law which tells us that the sum of forces is equal to the product of mass by acceleration.
∑F = m*a
Now replacing:
Ahora la potencia se puede calcular por medio del producto de la fuerza por velocidad.
where:
P = power [W]
F = force = 600 [N]
v = velocity = 9 [m/s]
1. The change in momentum follows the formula:
Change in Momentum = mΔv,
where m is the mass and v is the velocity
Change in momentum = (700 kg)(15 m/s - 30 m/s) =<em> -10,500 kg·m/s</em>
2. For this problem, the formula for impulse, J, is
J = FΔt
Before answering part a, we answer for part b first.
Part B.
F = ma
where
a = Δv/t = (15 - 30)/5 = -1 m/s²
So,
F = (700 kg)(-1 m/s²) = <em>-700 N</em>
Part A.
J = (-700 N)(5 s) =<em> -3,500 N·s</em>