Answer:
The force of gravitational attraction is 8.454 x 10⁻⁸ N.
Explanation:
Given;
mass of the boy, m₁ = 78 kg
mass of the girl, m₂ = 65 kg
distance between the boy and the girl, r = 2 meters
The force of gravitational attraction is given as;
where;
G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²
r is the distance between two masses, m₁ and m₂
Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.
#1
It's c, chronological.
#2
It's d, "Stacks of books need to be shelved".
Refer to the diagram shown below.
Define unit vectors along the x and y axes as respectively
Then the three successive displacements, written in component form, are respectively
The total displacement for the first leg of the trip is
Answer:
or (-0.6, 0.8)
Answer:
25104 J
Explanation:
We are given;
Mass; m = 600 g
Change in temperature;Δt = (40 - 30) = 10°C
Specific heat of water; c = 4.184 J/g°C
Now, to find how many joules, we simply use the formula for quantity of heat.
Thus;
Q = mcΔt
Plugging in the relevant values to give;
Q = 600 × 4.184 × 10
Q = 25104 J
Quantity of heat = 25104 J
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