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stepladder [879]
2 years ago
9

Which idea would most likely be dangerous for a student to think while entering a lab?

Physics
1 answer:
aleksley [76]2 years ago
3 0
Your answer should be a i can figure out how the tools work as i go along
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an object is moving in a straight line with a constant acceleration initially it is traveling at 16 meters per second. 3 seconds
VLD [36.1K]

A)It moved 6 meters.

B)It would 3 meters.

I think this is the answer.

Have a good day.

4 0
3 years ago
Using Planck’s constant as h = 6.63 E-34 J*s, what is the wavelength of a proton with a speed of 5.00 E6 m/s? The mass of a prot
Marrrta [24]
De Broglie's identity gives the relationship between the momentum and the wavelength of a particle:
p=mv= \frac{h}{\lambda}
where
p is the particle momentum
m is its mass
v its velocity
h is the Planck constant
\lambda is the wavelength

By re-arranging the equation, we get
\lambda=  \frac{h}{mv}
and by using the data about the proton, given in the text, we can find the proton's wavelength:
\lambda= \frac{h}{mv} = \frac{6.63 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.00 \cdot 10^6 m/s)} =7.99 \cdot 10^{-14} m
6 0
3 years ago
What fills the void between stars and galaxies.
Lana71 [14]
Answer: The voids between stars in our galaxy can be filled with tenuous clouds of gas and other molecules. ... That material gets "ripped away" from the galaxies by the force of gravity, and often enough it collides with other material.

HOPE IT HELPED:) HAVE A NICE DAY
6 0
3 years ago
Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 14 × 15 × 8.0ft. the density of air
vova2212 [387]
Since we are given the density and volume, then perhaps we can determine the amount in terms of the mass. All we have to do is find the volume in terms of cm³ so that it will cancel out with the cm³ in the density. The conversion is 1 ft = 30.48 cm. The solution is as follows:

V = (14 ft)(15 ft)(8 ft)(30.48 cm/1 ft)³ = 0.0593 cm³

The mass is equal to:
Mass = (0.00118g/cm³)(0.0593 cm³)
Mass = 7 grams of HCN
7 0
3 years ago
A lightweight string is wrapped several times around the rim of a small hoop. If the free end of the string is held in place and
MariettaO [177]

Answer:

Explanation:

Let T be the tension

For linear motion of hoop downwards

mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .

For rotational motion of hoop

Torque by tension

T x R ,      R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I  α

= I  a / R

a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

5 0
3 years ago
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