Answer:
yes it doesn't matter
Explanation:
it doesn't matter because troughs and crests are the same and either can be used
The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
![Work\;done = Force \times distance](https://tex.z-dn.net/?f=Work%5C%3Bdone%20%3D%20Force%20%5Ctimes%20distance)
<u>For </u><u>student 1</u><u>:</u>
![Work\;done = 500 \times 1.2](https://tex.z-dn.net/?f=Work%5C%3Bdone%20%3D%20500%20%5Ctimes%201.2)
Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>
![Work\;done = 500 \times 5](https://tex.z-dn.net/?f=Work%5C%3Bdone%20%3D%20500%20%5Ctimes%205)
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
Answer:
The equation of D = m/V
Where D = density
m = mass
and V = volume
We are solving for V, so with the manipulation of variables we multiply V on both sides giving us
V(D) = m
now we divide D on both sides giving us
V = m/D
We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3 or 200mL
a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
If you wish to change it to L, you'd have to convert
Explanation:
Explanation:
It is given that,
Spring constant of the spring, k = 15 N/m
Amplitude of the oscillation, A = 7.5 cm = 0.075 m
Number of oscillations, N = 31
Time, t = 15 s
(a) Let m is the mass of the ball. The frequency of oscillation of the spring is given by :
![f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B1%7D%7B2%5Cpi%7D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
Total number of oscillation per unit time is called frequency of oscillation. Here, ![f=\dfrac{31}{15}=2.06\ Hz](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B31%7D%7B15%7D%3D2.06%5C%20Hz)
![m=\dfrac{k}{4\pi^2f^2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bk%7D%7B4%5Cpi%5E2f%5E2%7D)
![m=\dfrac{15}{4\pi^2\times 2.06^2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B15%7D%7B4%5Cpi%5E2%5Ctimes%202.06%5E2%7D)
m = 0.0895 kg
or
m = 89 g
(b) The maximum speed of the ball that is given by :
![v_{max}=A\times \omega](https://tex.z-dn.net/?f=v_%7Bmax%7D%3DA%5Ctimes%20%5Comega)
![v_{max}=A\times 2\pi f](https://tex.z-dn.net/?f=v_%7Bmax%7D%3DA%5Ctimes%202%5Cpi%20f)
![v_{max}=0.075\times 2\pi \times 2.06](https://tex.z-dn.net/?f=v_%7Bmax%7D%3D0.075%5Ctimes%202%5Cpi%20%5Ctimes%202.06)
![v_{max}=0.970\ m/s](https://tex.z-dn.net/?f=v_%7Bmax%7D%3D0.970%5C%20m%2Fs)
![v_{max}=97\ cm/s](https://tex.z-dn.net/?f=v_%7Bmax%7D%3D97%5C%20cm%2Fs)
Hence, this is the required solution.