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fomenos
3 years ago
13

Testing shows that a sample of wood from an artifact contains 25% of the

Physics
2 answers:
daser333 [38]3 years ago
5 0

Answer:

The artifact is 11,460 years old.

<u>Explanation</u>:

Given that,

The half life of the carbon-14 is 5730  years and we are left with 255 of the sample of wood from an arti-fact.

So it takes 5730 years for the sample to reduce into half

Initially there will be 100% of the sample so

after first 5730 years, the sample reduces into 50% percent

Now the left 50% sample will take another 5730 years to decay into half of its amount.

after next 5730 years  the sample reduces into 25% percent

So totally after 2 half-life the sample reduces into 25%

That is (5730 +5730) years = 11460 years

Umnica [9.8K]3 years ago
3 0

Answer:5730 years

Explanation:

A P E X

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2 years ago
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A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf
lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf=E_{rms}=120 V

We have to find the length of the wire from which the coil is made.

Peak value of emf=E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V

Length of wire=4\sqrt{\frac{NE_0}{2\pi fB}}

Substitute the values

Length of wire=4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

6 0
3 years ago
Insulators will:
nalin [4]

Answer:

Inhibit the flow of electrons  

Explanation:

An electric current usually consists of electrons moving through a wire.

An insulator prevents the flow of an electric current, so it inhibits the flow of electrons.

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3 years ago
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The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
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