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4 years ago

2b + 8 - 5B +3 = -13+ 8B -5

Mathematics

2 answers:

Juliette [100K]4 years ago

4 0

8b2-10b2+3=0

Two solutions were found :

b = ±√ 1.500 = ± 1.22474

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((8 • (b2)) - (2•5b2)) + 3 = 0

Step 2 :

Equation at the end of step 2 :

(23b2 - (2•5b2)) + 3 = 0

Step 3 :

Trying to factor as a Difference of Squares :

3.1 Factoring: 3-2b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 3 is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

Equation at the end of step 3 :

3 - 2b2 = 0

Step 4 :

Solving a Single Variable Equation :

4.1 Solve : -2b2+3 = 0

Subtract 3 from both sides of the equation :

-2b2 = -3

Multiply both sides of the equation by (-1) : 2b2 = 3

Divide both sides of the equation by 2:

b2 = 3/2 = 1.500

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

b = ± √ 3/2

The equation has two real solutions

These solutions are b = ±√ 1.500 = ± 1.22474

Two solutions were found :

b = ±√ 1.500 = ± 1.22474

Nataly [62]4 years ago

4 0

Answer: b=2.4

Step-by-step explanation:

First you want to add the same things on the same side: 2b+(-5b) which equals -3b

Then do the same thing to this:8+3=11

Then:-13-5=-18

Which shows as: 8-3b= -18+8b

Then you take the smallest subscript: -3b and add itself to itself: -3b+3b=0

And do the same with the other subscript: 8b+3b=11b

Which shows as: 8=-18+11b

Then box the 11b and add the -18 to itself: -18+18=0

Do the same with the other side: 8+18=26

Which shows as: 26=11b

Then divide each side by 11.

Then this is your answer: b=2.4

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maxonik [38]

Answer with Step-by-step explanation:

We are given that

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$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

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$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

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