Answer:
Part a: 0.90 J
Part b: 4.5 J
Explanation:
Part a:
The particle of charge q=+8.2 μC will move from x=70cm to x=100cm:
dU=-dK
=(k*q*Q/r_f)-(k*q*Q/r_i)
= -(K_f-K_i)
= (9*10^9)*(8.2*10^-6)*(31*10^-6)/(1)-(9*10^9)*(7.5*10^-6)*(20*10^-6)
= -(K_f-0)
K_f= 0.90 J
Part b: The particle of charge q=+8.2 μC will move from x=70cm to x=20cm:
dU=-dK
=(k*q*Q/r_f)-(k*q*Q/r_i)
= -(K_f-K_i)
= (9*10^9)*(8.2*10^-6)*(-31*10^-6)/(0.2)-(9*10^9)*(7.5*10^-6)*(20*10^-6)
= -(K_f-0)
K_f= 4.5 J
All waves are known to undergo reflection or the bouncing off of an obstacle. Most people are very accustomed to the fact that light waves also undergo reflection. The reflection of light waves off of a mirrored surface results in the formation of an image.
Answer:
The answer is 24cm
Explanation:
This problem bothers on the curved mirrors, a concave type
Given data
Object height h= 5cm
Object distance = 12cm
Focal length f=24cm
Let the image distance be v=?
Applying the formula we have
1/v +1/u= 1/f
Substituting our given data
1/v+1/12=1/24
1/v=1/24-1/12
1/v=1-2/24
1/v=-1/24
v= - 24cm
This implies that the image is on the same side as the object and it is real
Answer:
Transform active margins are associated with which type of boundary?
Transform boundary
Explanation:
The transform boundary is a boundary where one plates(crust) slides past another plate horizontally. This kind of plate movement have been detected to exist between the interaction of the North pacific plates(continental plate) and the pacific plates(oceanic plates) .
At the transform margin the crust are usually broken. But overall crust are neither created nor destroyed . The transform margin region are active as it is marked by shallow-focus earthquakes .
Along the fractured zone where this transform movement occurs is known to create extensive transform faults .Notable transform fault that exist in this kind of boundary(transform) is the San Andrea fault and Alpine Fault.
The motion of this plates can occur on a single fault or on a group of faults.
