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Rasek [7]
3 years ago
15

If a Ferrari, with an initial velocity of 10m/s, accelerates at at rate of 50m/s/s for 3 seconds, what will its final velocity b

e?
Physics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

160 m/s

Explanation:

The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

v(t)= u +at

where

u = 10 m/s

a = 50 m/s^2

If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

v(3 s)=10 m/s + (50 m/s^2)(3 s)=160 m/s

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Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A
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The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Impulse:

The effect of applied force acting for a very small interval of time is known as Impulse.

Given data:

The initial magnitude of the force on Ball A is, F = 50 N.

The time interval for the applied force on Ball A is, t = 1.25 s.

And the impulse at initial on ball A is, I = 62.5 N-s.

Now, if force on ball A doubles, which means new magnitude of force is,

F' = 2F

F' = 2 × 50

F' = 100 N

For same time interval, the new impulse on Ball A is given as,

I' = F' × t

Solving as,

I' = 100 × 1.25

I' = 125 N-s

Taking the ratio of both the impulses as,

I' / I = 125/62.5

I' = 2 I

Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

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7 0
3 years ago
Read the scenario and solve these two problems. When traveling at top speed, a roller coaster train with a mass of 12,000 kg has
andreev551 [17]
First answer  5400000 
second answer 46
4 0
3 years ago
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A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
Can someone make a list of 10 simple things people can do to maintain fitness ? Please I literally need help.
ivanzaharov [21]

Answer:

1. drink lots of water

2. eat healthy breakfast

3. plan your meals

4. set a deadline

5. exercise at least 30 minutes a day even 10 minutes 3 times a day is good

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8. get a good night's sleep

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6 0
3 years ago
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A sound wave with a waveenght of 2.5 meters traves 660 meters in 2 seconds calculate the frequemcy of the wave to cacuation the
finlep [7]

The frequency of the wave is 132 Hz

Explanation:

To calculate the speed of the wave, we can use the following formula:

v = \frac{d}{t}

where

d is the distance travelled by the wave

t is the time elapsed

For the sound wave in this problem, we have:

d = 660 m is the distance travelled

t = 2 s is the time interval considered

Substituting and solving for v, we find the speed of the sound wave:

v=\frac{660}{2}=330 m/s

Now we can calculate the frequency of the wave by using the wave equation:

v=f\lambda

where

v = 330 m/s is the speed of the wave

\lambda=2.5 m is the wavelength

f is the frequency

Solving for f, we find:

f=\frac{v}{\lambda}=\frac{330}{2.5}=132 Hz

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3 years ago
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