Answer:
1568 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 80 Kg
Distance (d) = 5 m
Coefficient of kinetic friction (μ) = 0.4
Workdone (Wd) =?
Next, we shall determine the normal reaction. This can be obtained as follow:
Mass (m) = 80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?
N = mg
N = 80 × 9.8
N = 784 N
Next, we shall determine force of friction. This can be obtained as follow:
Coefficient of kinetic friction (μ) = 0.4
Normal reaction (N) = 784 N
Force of friction (F) =?
F = μN
F = 0.4 × 784
F = 313.6 N
Finally, we shall determine the work done. This can be obtained as follow:
Distance (d) = 5 m
Force of friction (F) = 313.6 N
Workdone (Wd) =?
Wd = F × d
Wd = 313.6 × 5
Wd = 1568 J
Thus, the workdone is 1568 J
