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nata0808 [166]
1 year ago
5

what minimum volume must the slab have for a 42.0 kg woman to be able to stand on it without getting her feet wet?

Physics
1 answer:
yawa3891 [41]1 year ago
8 0

0.525 m³ minimum volume must the slab have for a 42.0 kg woman to be able to stand on it without getting her feet wet.

<h3>How do you find the minimum volume?</h3>

Add the biggest possible inaccuracy to each metric, then multiply to get the biggest volume you can. Subtract the largest potential mistake of each measurement, then multiply, to determine the smallest volume that can be produced.

<h3>Briefing:</h3>

1000 kg/m³ = density of water

920 kg/m³ = density of ice

BF = Woman Weight + Slab Weight

Pvg = 42 + Pvg

V = 42 kg / (1000 - 920)

V = 42 / 80

V = 0.525 m³

To know more about Minimum volume visit:

brainly.com/question/28555971

#SPJ4

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A moped has a mass of 120kg . It accelerates at a rate of 2 m/s^2 . What is the size of the resultant force acting on it ?
stiv31 [10]

Answer:

240N

Explanation:

The formula for force is F=mass×acceleration.

Therefore, Force= 120×2= 240N

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3 years ago
If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?
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Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

5 0
3 years ago
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An astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Kamila [148]

Answer:

The answer is

<h2>28 kg</h2>

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

m =  \frac{p}{v}  \\

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

m =  \frac{280}{10}  = 28 \\

We have the final answer as

<h3>28 kg</h3>

Hope this helps you

3 0
3 years ago
Kamir and Alexis are studying the properties of water. They conducted a variety of experiments to determine its physical and che
solniwko [45]

The answer is D) neutral water reacts with carbon dioxide to form an acid solution

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Calculate the energy, wavelength, and frequency of the emitted photon when an electron moves from an energy level of -3.40 eV to
jasenka [17]

Answer:

(a) The energy of the photon is 1.632 x 10^{-8} J.

(b) The wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency of the photon is 2.47 x 10^{25} Hz.

Explanation:

Let;

E_{1} = -13.60 ev

E_{2} = -3.40 ev

(a) Energy of the emitted photon can be determined as;

E_{2} - E_{1} = -3.40 - (-13.60)

           = -3.40 + 13.60

           = 10.20 eV

           = 10.20(1.6 x 10^{-9})

E_{2} - E_{1} = 1.632 x 10^{-8} Joules

The energy of the emitted photon is 10.20 eV (or 1.632 x 10^{-8} Joules).

(b) The wavelength, λ, can be determined as;

E = (hc)/ λ

where: E is the energy of the photon, h is the Planck's constant (6.6 x 10^{-34} Js), c is the speed of light (3 x 10^{8} m/s) and λ is the wavelength.

10.20(1.6 x 10^{-9}) = (6.6 x 10^{-34} * 3 x 10^{8})/ λ

λ = \frac{1.98*10^{-25} }{1.632*10^{-8} }

  = 1.213 x 10^{-17}

Wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency can be determined by;

E = hf

where f is the frequency of the photon.

1.632 x 10^{-8}  = 6.6 x 10^{-34} x f

f = \frac{1.632*10^{-8} }{6.6*10^{-34} }

 = 2.47 x 10^{25} Hz

Frequency of the emitted photon is 2.47 x 10^{25} Hz.

6 0
2 years ago
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