Calculate the watts of power expended when a force 400 N travels 12 meters over 10 seconds.

A cruise ship has a mass of 100,000,000 kg and a kinetic energy of 5,000,000 kJ. Calculate the speed of the cruise ship.

KiRa [710]

Explanation:

K.E = 5,000,000 KJ

MASS = 100,000,000 Kg

K.E = 1/2 MV^2

$5000000 = \frac{1}{2} \times 100000000 \times v {}^{2}$

$5000000 = 50000000 \times v {}^{2}$

$v {}^{2} = \frac{5000000}{50000000}$

$v {}^{2} = \frac{5}{50}$

therefore

$v {}^{2} = \frac{1}{10}$

$v = \sqrt{0.1}$

v = 0.316 m/s^2

4 0

2 years ago

A 26.3 kg space rock is pushed with a force and accelerates at 12.82 m/s/s. How much force was applied?

Kazeer [188]

Answer: multiply mass and acceleration, unit is N (newtons)

Explanation: law of dynamics: F = ma

6 0

3 years ago

A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t

Nataly [62]

Answer:

Explanation:

Given

N0 = 20kg (original substance)

decay constant λ = 0.179/sec

time t = 300s

We are to find N(t)

Using the formula;

n(t) = N0e^-λt

Substitute the given values

N(t) = 20e^-(0.179)(300)

N(t) = 20e^(-53.7)

N(t) = 20(4.7885)

N(t) =143.055

To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152

About 7 times the original material is still radioactive

4 0

3 years ago

A superconducting solenoid has 3300 turns per meter and carries 4. 1 ka. Find the magnetic field strength in the solenoid.

WARRIOR [948]

The magnetic field strength is 17 Weber.

<h3>How can we find the value of magnetic field?</h3>

We know, The magnetic field equation is given by:

$B= \mu_{0} \times n \times I$

<h3>Given,</h3>

Where, we know,

$\mu_{0}$ = $4\pi \times 10^{7}$ $\frac{T. m^{2} }{A}$ = It is the magnetic constant or the permeability of free space.

n = The turn density which is equivalent to number of turns per unit length = 3300 turns per meter = 3300 $m^{-1}$

I= the amount of current applied to it = 4. 1 kA = 4 × $10^{3}$ A.

We have to find the magnetic field strength = B

Substituting the known values into the equation gives the strength of the magnetic field, which is:

$B= 4\pi \times 10^{7} \times (3300) \times 4.1 \times 10^{3}$

$B= 17 T.m$

$B= 17W$ [We know, $1 Tesla.meter = 1 Weber$ ]

So, from the above calculation we can see that, The magnetic field strength is 17 Weber.

Learn more about magnetic field :

brainly.com/question/26257705

#SPJ4

4 0

2 years ago

Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun

Nookie1986 [14]

Answer:

The answer is " $3.83 \times 10^9 \ m$ "

Explanation:

Z=2, so the equation is $E= \frac{-4B}{n^2}$

Calculate the value for E when:

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies

In this transition, the wavelength of the photon emitted is:

$\Delta E=2.18 \times 10^{-18} ( \frac{1}{4}- \frac{1}{81})$

$\lambda = \frac{h c}{\Delta E}$

$h ( Planck's\ constant) = 6.62 \times 10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times 10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\$

6 0

3 years ago