Answer:
<h3>Following are the properties and characteristics of the glass.</h3>
<h3>Hardness and Brittleness. It is a hard material as it has great impact resistance against applied load.</h3>
- Weather Resistance.
- Insulation.
- Chemical Resistance.
- Colour and Shape Varieties.
- Transparency.
- Fire Resistant Glazing.
- Property Modification.
Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.
Explanation:
- Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s
- Let
be the speed of the river's current given as 1.00 m/s.
- Note that this speed is the magnitude of the velocity which is a vector quantity.
- The direction of the swimmer is upstream.
Hence the resultant velocity is given as,
= S — S 0
= 1.25 — 1
= 0.25 m/s.
Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.
To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
![d = \frac{ \:Δv}{e}](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cfrac%7B%20%5C%3A%CE%94v%7D%7Be%7D%20)
![= \frac{1.5v}{100v/m}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1.5v%7D%7B100v%2Fm%7D%20)
![= 1.5 \times 10 {}^{ - 2} m](https://tex.z-dn.net/?f=%20%3D%201.5%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%202%7D%20m)
learn more about potential difference from here: brainly.com/question/28166044
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Answer:
the final velocity of the car is 59.33 m/s [N]
Explanation:
Given;
acceleration of the car, a = 13 m/s²
initial velocity of the car, u = 120 km/h = 33.33 m/s
duration of the car motion, t = 2 s
The final velocity of the car in the same direction is calculated as follows;
v = u + at
where;
v is the final velocity of the car
v = 33.33 + 13 x 2
v = 59.33 m/s [N]
Therefore, the final velocity of the car is 59.33 m/s [N]