OOF it is the same for both
2 answers:
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Answer:
E = 20.03 J
Explanation:
Given that,
The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,
Voltage, V = 12 V
We need to find the energy delivered to the lightbulb filament during 2.00 s.
The energy delivered is given by :
. ....(1)
As,
As per Ohm's law, V = IR
Using formula (1).
So, the energy delivered to the lightbulb filament is 20.03 J.