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Gemiola [76]
3 years ago
14

URGENT PLZ HELP

Chemistry
1 answer:
shutvik [7]3 years ago
5 0
I don’t want to be wrong but I’m gonna say 2p
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Using table 9.4, calculate an approximate enthalpy (in kj) for the reaction of 1.02 g gaseous methanol (ch3oh) in excess molecul
Tanya [424]

<u>Given:</u>

Mass of methanol = 1.02 g

<u>To determine:</u>

Enthalpy for the reaction of 1.02 g of methanol with excess O2

<u>Explanation:</u>

Balanced equation-

2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nH°f(products) - ∑nH°f(reactants)

where n = number of moles

H°f = standard enthalpy of formation.

ΔHrxn = [2H°f(CO2(g)) + 4H°f(H2O(g))] - [2H°f(CH3OH(g)) + 3H°f(O2(g))]

           = [2(-393.5) + 4(-241.8)]-[2(-201.5) + 3(0)] = -1351.2 kJ

Now, 1 mole of CH3OH = 32 g

The calculated ΔHrxn corresponds to 2 moles of CH3OH. i.e.

The enthalpy change for 64 g of Ch3OH = -1351.2 kJ

Therefore, for 1.02g gaseous methanol we have:

ΔH = 1.02 * -1351.2/64 = -21.5 kJ

Ans: The enthalpy for the given reaction is -21.5 kJ



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2 years ago
Decribe the difference between and climate.
earnstyle [38]
Between what and climate
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A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch
GuDViN [60]

Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})

= 0.075 mol HCl

100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = \frac{0.050mol}{0.350L}

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

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3 years ago
Which of the following is the proper scientific notation for the number 18,200?
satela [25.4K]
1.82 x 10^4 i believe
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