Answer:
The rate of appearance of hydrogen gas is 0.095 M/s.
Explanation:
Rate of the reaction is the change in concentration of of any one of the reactants or products per unit time.
Given:
The rate of disappearance of HBr = ![-\frac{d[HBr]}{dt}=0.190 M/s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BHBr%5D%7D%7Bdt%7D%3D0.190%20M%2Fs)
Rate of the reaction is given by:
![R=-\frac{1}{2}\frac{d[HBr]}{dt}=\frac{1}{1}\frac{d[H_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BHBr%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D)
![R=-\frac{1}{2}\frac{d[HBr]}{dt}=\frac{1}{2}\times 0.190 M/s=0.095 M/s](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BHBr%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.190%20M%2Fs%3D0.095%20M%2Fs)
Rate of appearance of the hydrogen gas:
![\frac{d[H_2]}{dt}=R =0.095 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3DR%20%3D0.095%20M%2Fs)
The rate of appearance of hydrogen gas is 0.095 M/s.
Answer:
Explanation:
20mL = 0.020L
0.115M = mol/0.02L
mol=0.0023
equivalence point → mols of weak acid = mols of strong base
0.1014 = 0.0023/volume
volume = 0.02268 L → 22.68 mL
The earths magnetic field revolves around it's magnetic poles.
The chemical reaction for this is:
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O
Solving for CO2 with each reactant will give:
21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2
mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O
110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x
(18 g H2O/1 mol H2O) = 53.04 g H2O
Since the amount of H2O in C2H6 is lower therefore C2H6
is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)
ANswer:
38 g water
Answer:
Explanation:
An example of binary compund is ZnI2 is zinc iodide
