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3 years ago

What is the speed od sail boat that us traveling 100 meters in 120 seconds?

1 answer:

3 0

The sailboat is about 0.83m/sec (rounded to the nearest tenth).

To find speed, you would calculate distance over time.

100 meters/120 seconds = 0.83 meters per second

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Q11) If you were standing at the top of a building and you dropped a rock.

Dafna1 [17]

Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

Where;

h = The height from which the object is dropped

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time taken to travel the distance, h = 5.2 s

∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m

The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

8 0

2 years ago

Visible light waves are ______ waves<br> A.mechanical <br> B.electromagnetic

motikmotik

B.Electromagnetic
explanation:

4 0

3 years ago

What happens to the mechanical energy of an apple as it falls from a tree?

Vikentia [17]

Answer:

When the apple falls from the tree, it has some gravitational potential energy due to its height. Now, When it starts falling, the Gravitation Potential energy will starts converting into the Kinetic Energy. When the apple is about to strikes the ground, the Gravitational Potential energy have been converted into the Kinetic Energy.

Explanation:

4 0

2 years ago

What is formulae method

GarryVolchara [31]

Answer:

Explanation:

The formula method is used to calculate termination payments on a prematurely ended swap, where the terminating party compensates the losses borne by the non-terminating party due to the early termination.

6 0

3 years ago

A golf ball is given an initial velocity of 100 m/s at an angle of 22o with the horizontal. The golf ball lands on the roof of a

hoa [83]

a) 92.7 m/s, 37.5 m/s

The initial horizontal and vertical velocity are given by the equations:

$u_x = u cos \theta\\u_y = u sin \theta$

where

u = 100 m/s is the initial velocity of the ball

$\theta=22^{\circ}$ is the angle of projection

So, the horizontal component of the initial velocity is

$u_x = (100)(cos 22)=92.7 m/s$

While the vertical component is

$u_y = (100)(sin 22)=37.5 m/s$

b) 3.83 s

The time at which the ball reaches the maximum height can be found by analyzing the vertical motion only.

In fact, the vertical velocity of the ball is given by

$v_y = u_y +at$

where

$u_y = 37.5 m/s$

$a=g=-9.8 m/s^2$ is the acceleration of gravity (in the downward direction)

t is the time

The ball reaches the maximum height when the vertical velocity becomes zero:

$v_y = 0$

So, solving for t, we find the time at which this happens:

$t=-\frac{u_y}{g}=-\frac{37.5}{9.8}=3.83 s$

c) 92.7 m/s

As stated in part b), the vertical velocity of the ball at the maximum height is zero:

$v_y = 0$

Along the horizontal direction, insteand, the motion of the ball is uniform, since there are no forces acting in this direction. Therefore, the horizontal velocity of the ball is constant (because the horizontal acceleration is zero), and it is

$v_x = u_x = 92.7 m/s$

And therefore, the velocity of the ball at the maximum height is simply equal to the horizontal velocity:

$v=92.7 m/s$

d) 71.7 m

The maximum height of the ball can be found by studying again the vertical motion only, by using the following suvat equation:

$s=u_yt+\frac{1}{2}at^2$

where

s is the vertical displacement at time t

$u_y = 37.5 m/s$

$a=g=-9.8 m/s^2$

We know that the ball reaches the maximum height when t = 3.83 s, so we can find the vertical displacement at that time:

$s=(37.5)(3.83)+\frac{1}{2}(-9.8)(3.83)^2=71.7 m$

So, the maximum heigth is 71.7 m.

e) 5.93 s

We know that the ball lands on a building whose height is

h = 50 m

This means that when the ball lands, its vertical displacement is

s = 50 m

So, we can use again the equation

$s=u_yt+\frac{1}{2}at^2$

To find t, the time at which the ball lands. Substituting:

$u_y = 37.5 m/s$

$a=g=-9.8 m/s^2$

s = 50 m

The equation becomes

$50=37.5 t -4.9 t^2\\4.9t^2 -37.5 t +50 = 0$

which gives two solutions:

t = 1.72 s

t = 5.93 s

The first solution is the moment at which the ball reaches the height of h = 50 m for the first time (before reaching its maximum height), so we ignore it, and therefore the ball lands after

t = 5.93 s

8 0

3 years ago

What is the speed od sail boat that us traveling 100 meters in 120 seconds?​

What is the speed od sail boat that us traveling 100 meters in 120 seconds?