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2 years ago

What is the speed od sail boat that us traveling 100 meters in 120 seconds?

1 answer:

3 0

The sailboat is about 0.83m/sec (rounded to the nearest tenth).

To find speed, you would calculate distance over time.

100 meters/120 seconds = 0.83 meters per second

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Which contributions did Johannes Kepler make? Check all that apply. He revived Aristotle's model of the solar system. He solved

Arada [10]

The correct answers are: Options 2,4 and, 5

2)He solved Ptolemy’s model by proving elliptical orbits.

4)He determined that planets move faster when closer to the Sun.

5)He discovered laws of planetary motion.

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3 years ago

Read 2 more answers

Help me please!

MrMuchimi

I think it’s A
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2 years ago

A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head

Irina-Kira [14]

Answer:

16.53 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 18.0 m/s.

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 18² – (2 × 9.8 × h)

0 = 324 – 19.6h

Rearrange

19.6h = 324

Divide both side by 19.6

h = 324 / 19.6

h = 16.53 m

Therefore, the maximum height reached by the ball is 16.53 m

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2 years ago

Complete the hypothesis statement by filling in the blank. The best answer gets brainlist

stepladder [879]

Answer:

<em>If the amount of water in the glass is close to brimming, then the pitch will ring as high-toned. </em>

Hope it helped :)

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2 years ago

Read 2 more answers

A charge of 50 µC is placed on the y axis at y = 3.0 cm and a 77-µC charge is placed on the x axis at x = 4.0 cm. If both charge

zheka24 [161]

Answer:

The acceleration of an electron is $1.2\times10^{20}\ m/s^2$

Explanation:

Given that,

One Charge = 50 μC

Distance on y axis = 3.0 cm

Second charge = 77 μC

Distance on x axis = 4.0 cm

We need to calculate the force on electron due to q₁

Using formula of force

$F_{1}=\dfrac{kq_{1}q}{r^2}$

Here, q = charge of electron

Put the value into the formula

$F_{1}=\dfrac{9\times10^{9}\times50\times10^{-6}\times1.6\times10^{-19}}{(3\times10^{-2})^2}$

$F_{1}=8\times10^{-11}j\ \ N$

We need to calculate the force on electron due to q₂

Using formula of force

$F_{2}=\dfrac{kq_{2}q}{r^2}$

Here, q = charge of electron

Put the value into the formula

$F_{2}=\dfrac{9\times10^{9}\times77\times10^{-6}\times1.6\times10^{-19}}{(4\times10^{-2})^2}$

$F_{2}=6.93\times10^{-11}i\ \ N$

We need to calculate the net force

Using formula of net force

$F=F_{1}+F_{2}$

Put the value into the formula

$F=8\times10^{-11}j+6.93\times10^{-11}i$

The magnitude of the net force

$F=\sqrt{(8\times10^{-11})^2+(6.93\times10^{-11})^2}$

$F=1.058\times10^{-10}\ N$

We need to calculate the acceleration of an electron

Using formula of force

$F = ma$

$a=\dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{1.058\times10^{-10}}{9.1\times10^{-31}}$

$a=1.2\times10^{20}\ m/s^2$

Hence, The acceleration of an electron is $1.2\times10^{20}\ m/s^2$

3 0

3 years ago

What is the speed od sail boat that us traveling 100 meters in 120 seconds?​

What is the speed od sail boat that us traveling 100 meters in 120 seconds?