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lubasha [3.4K]
3 years ago
9

How many elements are found in the following chemical equation? K + Cl → KCl A. 1 B. 2 C. 3 D. 0

Chemistry
2 answers:
Gnesinka [82]3 years ago
5 0
K is Potassium
Cl is Chlorine 
There are 2 elements.
Margaret [11]3 years ago
3 0

Answer: Option (B) is the correct answer.

Explanation:

An element is defined as a substance that contains same type of atoms.

For example, element K contains only atoms of potassium.

Whereas a substance in which two or more different elements chemically combine together in a fixed ratio by mass is known as a compound.

For example, KCl contains atoms of K and Cl in 1 : 1 ratio. Hence, it is a compound.

Therefore, in the chemical reaction, K + Cl \rightarrow KCl there are only two elements which are K and Cl.

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How many atoms of lead are contained in 0.532mol?​
Colt1911 [192]

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

6 0
4 years ago
Which societal problem can be solved, in part, by scientists identifying areas of high biodiversity?
MatroZZZ [7]
I thinks it's C although I'm not 100% positive.
6 0
3 years ago
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Una pieza de silicio tiene un volumen de 8 cm3. ¿Cuál es su masa? *
Maurinko [17]

Answer:

el volumen es igual a masa decidida por densidad

8 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
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docker41 [41]

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