There is no effect on earth's orbit due to similar force of gravity of black hole.
<h3> How would Earth's orbit change?</h3>
If our Sun was replaced with a black hole having the same mass, Earth's orbit will not changed because of the same force of gravitation of balck hole on earth. Due to this replacement, Earth's temperature will change because balck hole is not too hot like sun.
So we can conclude that there is no effect on earth's orbit due to similar force of gravity of black hole.
Learn more about sun here: brainly.com/question/15837114
Because the two paths are perpendicular, therefore the
target proton's new path must be at 30 degrees from the original
direction.
Using the law of conservation of momentum about the original direction:
m (400 m/s) = m (v1) cos(60) + m (v2) cos(30)
Cancelling m since the two protons have similar mass.
(v1)cos(60) + (v2)cos(30) = 500 m/s ---> 1
Now by using the law conservation of momentum perpendicular to the original
direction:
m (0 m/s) = m (v1) sin(60) – m (v2) sin(30)
Which simplifies to:
(v1)sin(60) - (v2)sin(30) = 0 m/s
v2 = v1 * sin(60) / sin(30) = v1 * sqrt(3) ---> 2
Plugging equation 2 to equation 1:
(v1) (1/2) + (v1 * sqrt(3)) sqrt(3)/2 = 500 m/s
(1/2) (v1) + (3/2) (v1) = 500 m/s
2 (v1) = 500 m/s
v1 = 250 m/s
Thus, from equation 2:
v2 = v1*sqrt(3) = (250 m/s) sqrt(3) = 433.01 m/s
So,
A. The target proton's speed is about 433 m/s
B. The projectile proton's speed is 250 m/s
Answer and Explanation:
The collision of particles (or moleclues) would need to be required. Say there are two gasses, one with a higher temperature and one with a lower one. The kenetic energy in the moleclues can move in random directions, and start to bump into each other. If the warmer particle collides with the cooler one then the warmer particle would be transferring <em>heat </em>which is thermal energy.<em> T</em>he particles colliding would be called <em>thermal conduction</em>.