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3 years ago

What is a sentence for absolute strength?

Physics

1 answer:

Zarrin [17]3 years ago

6 0

Her muscles were flaring with the blood coursing through her muscles.

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Molecular orbital theory correctly predicts paramagnetism of oxygen gas. true or false

PtichkaEL [24]

Answer: Yes.

Explanation:

Oxygen has a bond order of two. The bond order of Oxygen molecule is calculated, where the [eight valence electrons in bonding molecular orbitals minus (-) four valence electrons in antibonding molecular orbitals]/2 in the electron configuration.

Atoms/molecules where electrons are paired are diamagnetic (repelled by both poles of a magnetic); while atoms/molecules that have one or more unpaired electrons are paramagnetic (attracted to magnetic field).

The two unpaired electrons of dioxygen molecules has made it paramagnetic. By pouring liquid oxygen between the poles of a strong magnet, the liquid stream will be contained by the filed and fills up the space between the poles.

3 0

3 years ago

Porfavor ayuden que es pa mañana :v

Tpy6a [65]

Answer:

what language is

thattranslate i will.answer then

3 0

3 years ago

An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e

timama [110]

Answer:

K = 80.75 MeV

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

The proton mass is equal to the antiproton mass, so:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0

3 years ago

Express newton pascal joule and watt in fundamental unit

Nadya [2.5K]

i added an image. i hope it helped :)

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3 years ago

In this lab you will use a cart and track to explore various aspects of motion. You will measure and record the time it takes th

Keith_Richards [23]

It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.

Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.

3 0

3 years ago

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