The presence of which reactant is the best indicator of an oxidation-reduction reaction? KNO3 H2SO4 NaOH H2

2 answers:

5 0

The presence of which reactant is the best indicator of an oxidation-reduction reaction?
KNO3H2SO4NaOHH2

H2!

zvonat [6]3 years ago

4 0

<h3>Answer;</h3>

Hydrogen gas (H2)

<h3>Explanation;</h3>

Oxidation involves the loss of electrons while reduction is the gaining of electrons. Oxidation-reduction reaction is a reaction which involves the gaining of electrons and loss of electrons.
Oxidation may also be referred to as increase in the oxidation state of an atom while reduction is the decrease of oxidation state of an atom.
The presence of hydrogen gas as a reactant is a best indicator of an oxidation-reduction reaction. This is because in hydrogen gas hydrogen has a zero oxidation number which may increase to show oxidation or may decrease to show reduction after the reaction.

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The hydrogen atom is not actually electronegative enough to form bonds to xenon. were the xenon-hydrogen bond to exist, what wou

Marat540 [252]

Answer : The structure of $XeH_4$ will be square-planar.

Explanation :

In the given molecule $XeH_4$ , 'Xe' is the central atom and 'H' is the terminal atom.

Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.

The number of electrons used in Xe-H bonding = 8 electrons

The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons

There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.

The structure of $XeH_4$ is shown below.