Answer:
(i). C6H2COOH and Na2CO3(aq)
observation: <u>Bubbles</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>colourless</u><u> </u><u>gas</u><u> </u><u>(</u><u>carbon</u><u> </u><u>dioxide</u><u> </u><u>gas</u><u>)</u>
(ii) CH3CH2CH2OH and KMnO4 /H
observation: <u>The</u><u> </u><u>orange</u><u> </u><u>solution</u><u> </u><u>turns</u><u> </u><u>green</u><u>.</u>
[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>oxidation</em><em> </em><em>of</em><em> </em><em>propanol</em><em> </em><em>to</em><em> </em><em>propanoic</em><em> </em><em>acid</em><em> </em><em>occurs</em>]
(iii) CH3CH2OH and CH3COOH + conc. H2SO4
observation: <u>A</u><u> </u><u>sweet</u><u> </u><u>fruity</u><u> </u><u>smell</u><u> </u><u>is</u><u> </u><u>formed</u><u>.</u>
[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>an</em><em> </em><em>ester</em><em>,</em><em> </em><em>diethylether</em><em> </em><em>is</em><em> </em><em>formed</em><em>]</em>
(iv) CH3CH = CHCH3 and Br2 /H2O
observation: <u>a</u><u> </u><u>brown</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>formed</u><u>.</u>
Considering the definition of mass volume percentage, the percent concentration of dextrose is 45%.
<h3>Mass volume percentage</h3>
Mass volume percentage (% m/V) is a measure of concentration that indicates the number of grams of solute per 100 volume units of the solution. In other words, the volume percent of a component in the solution is defined as the ratio of the mass of the component to the volume of the solution, expressed as a percentage.
The mass volume percentage of a solution is determined by the following expression:
<h3>Percent concentration in this case</h3>
In this case, you know:
- mass of solute= 450 grams
- volume of solution= 1 L= 1000 mL
Replacing in the definition of mass volume percentage:
Solving:
<u><em>mass volume percentage= 45%</em></u>
Finally, the percent concentration of dextrose is 45%.
Learn more about mass volume percentage:
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The concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.
<h3>What is the balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen?</h3>
The balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen is given below as:
The addition of more sulfur trioxide to the bottle will result in increase in the volume of oxygen present as equilibrium will shift towards formation of products.
The addition of more sulfur dioxide to the bottle will result in decrease in the volume of oxygen present as equilibrium will shift towards formation of sulfur trioxide due to increase in product concentration.
Based on the graph, if the bottle is sealed, the concentration of sulfur trioxide will remain in dynamic equilibrium with the concentration of the products after the second day.
Based on the above information and reaction, the best way to reduce the amount of SO3 in the atmosphere, and thus reduce the amount of acid rain is to allow it to decompose before emission into the atmosphere,
Therefore, the concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.
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Morals can not be tested by science because different people have different morals. Science can not test Morlas and Ethics.