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joja [24]
3 years ago
11

The element oxygen has _____ valence electrons. (Input only a whole number, such as 7.)

Chemistry
2 answers:
kipiarov [429]3 years ago
8 0
Remark
The short Answer is 6. That's why the ion has a charge of minus 2. Oxygen is doing it's best to have its outer ring have 8 electrons which is the number of outer electrons contained in the outer ring of the Noble Gas Neon.

Answer 6.
Neko [114]3 years ago
8 0
Looking at the periodic table, oxygen is in group 6A, meaning it has 6 valence electrons. Another way to determine this is look for the noble gas in the same row as the element whom's valence electrons you wish to find and subtract 1 valence electron from 8 until you reach the desired element. This will be your amount of valence electrons :)
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using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

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