The balanced equation for the neutralisation reaction is as follows
Ca(OH)₂ + H₂SO₄ ---> CaSO₄ + 2H₂O
stoichiometry of Ca(OH)₂ to H₂SO₄ is 1:1
equivalent number of acid reacts with base
number of H₂SO₄ mol reacting - 2 mol
according to molar ratio of 1:1
number of Ca(OH)₂ mol = number of H₂SO₄ moles
therefore number of Ca(OH)₂ moles required - 2 mol
What question? Lhh this is hilarious.
The compound ch3ch2-sh is in the organic family know as c. thiols
Answer: 
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,:


where,
= initial pressure of gas = 101.3 kPa
= final pressure of gas = 94.6 kPa
= initial volume of gas = 20.0 ml
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get the final volume of gas.


Thus the correct numerical setup for calculating the new volume is 