Answer:
The average force the golf club exerts on the ball is 600 N
Explanation:
Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced
F = m× (v₂ - v₁)/(Δt)
The given parameters of the motion of the ball are;
The mass of the ball, m = 45 g = 0.045 kg
The initial velocity of the ball, v₁ = 0 m/s
The speed with which the ball was hit by the golfer, v₂ = 40 m/s
The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)
By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;
F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N
The average force the golf club exerts on the ball = F = 600 N.
Answer:
Geology Notes
1 Veryovkina Cave 2212[1] 13.5 km (8.4 mi)[1] Abkhazia / Georgia 43°23′52″N 40°21′37″E.
Answer:
I can't see the picture
Explanation:
Im sorry can you right whats on the picture down in the comments plz.
Answer:
The electric field strength is 
Explanation:
Given that,
Magnetic field = 0.150 T
Speed 
We need to calculate the electric field strength
Using formula of velocity
Where, v = speed
B = magnetic field
Put the value into the formula
Hence, The electric field strength is
Answer:
130m
Explanation:
You just have to multiply velocity by the time traveled:
100m/s * 1.3s = 130m!
